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3 years ago

Please can someone explain the answer to number 11

Chemistry

1 answer:

Aleks04 [339]3 years ago

7 0

Answer:

HClO2 is the Lewis Acid and the ClO2- is the Lewis Base in the first pair

NH3 is the Lewis Base and the NH4+ is the Lewis Acid in the second pair.

Explanation:

A Lewis Base is an electron donor so there are extra pairs of electrons.

A Lewis Acid is an electron receiver so they are electron deficient.

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2 years ago

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3 years ago

For her science project, Paula wants to determine if the growth of bacteria in standing rainwater changes over time. She collect

tamaranim1 [39]

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2 years ago

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3 years ago

Read 2 more answers

If a 7.0 mL sample of vinegar was titrated to the stoichiometric equivalence point with 7.5 mL of 1.5M NaOH, what is the mass pe

NNADVOKAT [17]

First we need to calculate the number of moles of NaOH titrated.

molar concentration = number of moles / solution volume (liter)

number of moles = molar concentration × solution volume

number of moles of NaOH = 1.5 × 0.0075 = 0.01125 moles

Then we look at the chemical reaction:

CH $_{3}$ -COOH + NaOH = CH $_{3}$ COONa + H $_{2}$ O

We can see that 1 mole of acetic acid is reacting with one mole of sodium hydroxide. Then we can conclude that 0.01125 moles of sodium hydroxide reacts with 0.01125 moles of acetic acid.

Now we can get the mass of acetic acid:

number of moles = mass (grams) / molecular mass (g/mol)

mass = number of moles × molecular mass

mass of acetic acid = 0,01125 × 60 = 0.675 g

We assume that the density of the vinegar = 1 g/mL, so the mass percent of acetic acid is:

concentration of acetic acid = (mass of acetic acid / mass of vinegar) × 100

concentration of acetic acid = (0.674 / 7) × 100 = 9.6 %

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2 years ago