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pantera1 [17]
3 years ago
7

Please helpp! ill mark brainlist (no bots or links ill report u)

Chemistry
2 answers:
raketka [301]3 years ago
7 0

Answer:

D)

Explanation:

The heat from the mantle makes the rocks at the bottom of lithosphere slightly soft. This causes the plates to move. The movement of these plates is known as plate tectonics.

ruslelena [56]3 years ago
5 0
Plates at our plantes surface move because of the intense heat in the earth core that causes molten rock in the mantle layers to move. It moves in a pattern called a convection cell that forms when warm material rises, cools and eventually sink down. As the cooled materials sink down, it is warmed and rises again.
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What determines the strength of a dipole-dipole force?
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hope this helps you :)

Explanation:

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4 years ago
A mixture of carbon dioxide and hydrogen gases is maintained in a 6.68 L flask at a pressure of 2.14 atm and a temperature of 19
matrenka [14]

Answer:

The mass of hydrogen gas in the mixture: <u>w₂ = 0.433 g</u>

Explanation:

<u>According to the ideal gas equation: </u>

for an ideal gas, P.V = n_{total}.R.T

and n_{total}= n_{1}+n_{2}

Here, P: total pressure of the gases = 2.14 atm  

V: total volume of the gases = 6.68 L

T: temperature = 19 °C = 19+273.15 = 292.15K        (∵ 0°C = 273.15K)

R:  gas constant = 0.08206 L·atm·K⁻¹·mol⁻¹

n_{total}: total number of moles of gases

<u>To calculate the total number of moles of gases</u>:

n_{total} = \frac{P.V}{R.T} = \frac{2.14 atm\times 6.68 L}{0.08206 LatmK^{-}mol^{-}\times 292.15K} = <u>0.5963 moles</u>

Let, the number of moles of carbon dioxide be n₁ and number of moles of hydrogen be n₂

<u>Given:</u> mass of carbon dioxide: w₁ = 16.8 g, mass of hydrogen: w₂ = ?g

molar mass of carbon dioxide: m₁ = 44.01 g/mol, molar mass of hydrogen: m₂= 2.016 g/mol

Therefore, n_{total}= n_{1}+n_{2} =  (w₁ ÷ m₁) + (w₂ ÷ m₂)

⇒ 0.5963 mol =  (16.8 g ÷ 44.01 g/mol) + (w₂ ÷ 2.016 g/mol)

⇒ 0.5963 mol =  (0.3817mol) + (w₂ ÷ 2.016 g/mol)

⇒ 0.5963 mol - 0.3817mol = (w₂ ÷ 2.016 g/mol)

⇒ 0.2146 mol = (w₂ ÷ 2.016 g/mol)

⇒ w₂ = 0.433 g

<u>Therefore, the mass of hydrogen gas in the mixture: w₂ = 0.433 g</u>

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