Answer:
1) = 9³
2) = 4*4*4*4*4
= 4 to the fifth power
Step-by-step explanation:
Answer:
option c is the correct.
Step-by-step explanation:
![\frac{2x^4*6x^2}{3x^2}](https://tex.z-dn.net/?f=%5Cfrac%7B2x%5E4%2A6x%5E2%7D%7B3x%5E2%7D)
by using the laws of exponent
a^m×a^n=a^m+n
12x^4+2/3x²
![\frac{12x^4}{3x^3}](https://tex.z-dn.net/?f=%5Cfrac%7B12x%5E4%7D%7B3x%5E3%7D)
4x^4-3
4x³
Yes but you get a decimal answer
Divide 28 by 3 and count how many are left over.
28 / 3 = 9 1/3
So each boy had 9 toy cars, and because you can't have 1/3 cars, you round 1/3 to 1. So there was 1 left over car.