What is the simplified form of square root of 45?

Carol's starting pay for her summer job is $10.25 per hour. Carol earns exactly 3 raises this summer.

kvv77 [185]

She starts off with $10.25 and gets a raise of $0.50, so she earns $10.75 per hour. Then she gets a raise of 10%, so then 10.75 x 0.10 = 1.075, so she earns $11.825 per hour. Then her third raise is $0.50 so she earns $12.325 per hour. The raise for next summer is 5%, so 12.325 x 0.05 = 0.61625, so she earns $12.94125.
She will earn about $12.94 per hour starting off next summer.

6 0

3 years ago

According to the norms established for a reading comprehension test, eighth-graders should average 83.2 with a standard deviatio

joja [24]

Answer:

$t=\frac{86.7-83.2}{\frac{8.6}{\sqrt{45}}}=2.73$

$p_v =P(t_{44}>2.73)=0.0045$

If we compare the p value and a significance level given $\alpha=0.01$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the population mean is signficantly higher than 83.2 at 1% of significance.

Step-by-step explanation:

Data given and notation

$\bar X=86.7$ represent the average life for the sample

$s=8.6$ represent the population standard deviation

$n=45$ sample size

$\mu_o =83.2$ represent the value that we want to test

$\alpha=0.01$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to apply a two tailed test.

What are H0 and Ha for this study?

Null hypothesis: $\mu \leq 83.2$

Alternative hypothesis : $\mu > 83.2$

Compute the test statistic

The statistic for this case is given by:

$t=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{86.7-83.2}{\frac{8.6}{\sqrt{45}}}=2.73$

Give the appropriate conclusion for the test

First we need to calculate the degrees of freedom given by:

$df=n-1=45-1=44$

Since is a one side right tailed test the p value would be:

$p_v =P(t_{44}>2.73)=0.0045$

Conclusion

If we compare the p value and a significance level given $\alpha=0.01$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the population mean is signficantly higher than 83.2 at 1% of significance.

8 0

3 years ago

3) Find the volume of this solid: *<br> cm<br> 2 cm

pentagon [3]

Answer:

what solid??????

Step-by-step explanation:

3 0

3 years ago

The multiplication principle of probability is used to find probabilities of compound events. True or false

Ksivusya [100]

That statement seems to be true