Answer:
1. They both uses same energy
2. The 6 kg ball requires more power than 3kg ball
Explanation:
Sample 1
m = 3kg
g= 10m/s^2
h = 2m
t = 2secs
W = mgh = 3 x 10 x 2 = 60J
P= w/t = 60/2 = 30watts
Sample 2
m = 6kg
g= 10m/s^2
h = 1m
t = 1sec
W = mgh = 6 x 10 x 1 = 60J
P= w/t = 60/1 = 60watts
They both uses same energy but different power. The 6 kg ball requires more power than 3kg ball
Answer:
A. the magnitude of the force between the spheres is 3.97 x 10⁻⁴ N
B. the magnitude of its initial acceleration is 5.83 m/s²
Explanation:
given information:
metal sphere's mass, m = 0.1 g = 1 x 10⁻⁴ kg
charge, q = -21 nC = -2.1 x 10⁻⁸
r = 10 cm = 0.1 m
What is the magnitude of the force between the spheres?
F₁₂ = k q₁q₂/r²
= ( 9 x 10⁹) (-2.1 x 10⁻⁸)²/(0.1)²
= 3.97 x 10⁻⁴ N
If the upper sphere is released, it will begin to fall. What is the magnitude of its initial acceleration?
mg - F₁₂ = ma
a = g - (F₁₂/m)
= 9.8 - (3.97 x 10⁻⁴/1 x 10⁻⁴)
= 5.83 m/s²
Answer:
2697.75N/m
Explanation:
Step one
This problem bothers on energy stored in a spring.
Step two
Given data
Compression x= 2cm
To meter = 2/100= 0.02m
Mass m= 0.01kg
Height h= 5.5m
K=?
Let us assume g= 9.81m/s²
Step three
According to the principle of conservation of energy
We know that the the energy stored in a spring is
E= 1/2kx²
1/2kx²= mgh
Making k subject of formula we have
kx²= 2mgh
k= 2mgh/x²
k= (2*0.01*9.81*5.5)/0.02²
k= 1.0791/0.0004
k= 2697.75N/m
Hence the spring constant k is 2697.75N/m
