Answer:
We know that in the decay process the sum of molecular number as well as molecular weight should be constant.
The following three reaction are as follows
1 .
Alpha decay of parent nuclide
The molecular number of alpha particle is 2 and molecular weight is 4 g/mol.
2.
Beta decay of daughter nuclide
v is the neutrino emission,The charge on the beta particle is zero.
3.
Alpha decay
A 5kg backpack will weigh 49 newtons on earth
6000 ml
There are 1000ml in one liter
Answer:
Explanation:
a ) It is given that bomb was at rest initially , so , its momentum before the explosion was zero.
b ) We shall apply law of conservation of momentum along x and y direction separately because no external force acts on the bomb.
If v be the velocity of the third part along a direction making angle θ
with x axis ,
x component of v = vcosθ
So momentum along x axis after explosion of third part = mv cosθ
= 10 v cosθ
Momentum along x of first part = - 5 x 42 m/s
momentum of second part along x direction =0
total momentum along x direction before explosion = total momentum along x direction after explosion
0 = - 5 x 42 + 10 v cosθ
v cosθ = 21
Similarly
total momentum along y direction before explosion = total momentum along y direction after explosion
0 = - 5 x 38 + 10 v sinθ
v sinθ= 21
squaring and and then adding the above equation
v² cos²θ +v² sin²θ = 21² +19²
v² = 441 + 361
v = 28.31 m/s
Tanθ = 21 / 19
θ = 48°
Should be true.
it's been awhile since I was learning this
