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Sladkaya [172]
3 years ago
15

A student's tonsils become infected and she has them removed. What condition does she need to be careful of in the future?

Physics
1 answer:
olya-2409 [2.1K]3 years ago
5 0

Answer:

she will have a reduced ability to fight airborne pathogen.

Explanation:

This is because the tonsils have an ability to fight airborne diseases as well as protect the body from pathogens

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Where are alkaline earth metals found on the periodic table?
mojhsa [17]

Answer:

B

Explanation:

8 0
2 years ago
After being struck by a bowling ball, a 1.3 kg bowling pin sliding to the right at 5.0 m/s collides head-on with another 1.3 kg
GuDViN [60]

Answer:

a) 4.2m/s

b) 5.0m/s

Explanation:

This problem is solved using the principle of conservation of linear momentum which states that in a closed system of colliding bodies, the sum of the total momenta before collision is equal to the sum of the total momenta after collision.

The problem is also an illustration of elastic collision where there is no loss in kinetic energy.

Equation (1) is a mathematical representation of the the principle of conservation of linear momentum for two colliding bodies of masses m_1 and m_2 whose respective velocities before collision are u_1 and u_2;

m_1u_1+m_2u_2=m_1v_1+m_2v_2..............(1)

where v_1 and v_2 are their respective velocities after collision.

Given;

m_1=1.3kg\\u_1=5m/s\\m_2=1.3kg\\u_2=0m/s

Note that u_2=0 because the second mass m_2 was at rest before the collision.

Also, since the two masses are equal, we can say that m_1=m_2=m so that equation (1) is reduced as follows;

mu_1+mu_2=mv_1+mv_2\\\\m(u_1+u_2)=m(v_1+v_2)..............(2)

m cancels out of both sides of equation (2), and we obtain the following;

u_1+u_2=v_1+v_2.............(3)

a) When v_1=0.8m/s, we obtain the following by equation(3)

5+0=0.8+v_2\\hence\\v_2=5-0.8\\v_2=4.2m/s

b) As m_1 stops moving v_1=0, therefore,

5+0=0+v_2\\v_2=5m/s

5 0
3 years ago
Write two units for electric field intensity and show thier equivalence?​
nataly862011 [7]

Answer:

Electric field intensity is the force experienced by a test charge q in a electric field E.

7 0
3 years ago
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PLS HELP. WILL MARK AS THE BRAINLIEST. PLS ANSWER STEP BY STEP.
USPshnik [31]

Answer:12

Explanation:

its the way u read it

3 0
3 years ago
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A weightlifter presses a 400 n weight 0.5 m over his head in 2 seconds, what is the power of the weight lifter
Scrat [10]
There are two ways to solve this problem. First we write the given.

Given: Force F = 400 N;  Height h = 0.5 m;  Time t = 2 s

Formula: P = W/t;  but Work W = Force x distance or W = f x d
 
Weight is also a Force, therefore:  W = mg, solve for Mass m = ?

m = w/g  m = 400 N/9.8 m/s²  m = 40.82 Kg

P = W/t = F x d/t  = mgh/t  P = (40.82 Kg)(9.8 m/s²)/2 s  

P = 100 J/s or 100 Watts

3 0
3 years ago
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