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Sedaia [141]
3 years ago
15

which number should be placed before F2 on the reactants side equation to make equation balanced? Xe + ___F2 > XeF4

Chemistry
2 answers:
jolli1 [7]3 years ago
5 0

Answer:

The number that should be placed before F₂ is 2

Explanation:

For a chemical reaction to be balanced we need to have the same amount of mass in the reactants and in the products because by the<em> law of conservation of mass</em>, mass cannot be created or destroyed.

We can acomplish this by having the same amount of atoms of each element in the reactant side that in the product side.

For example:

C₃H₈ + 5O₂ → 3CO₂ + 4H₂0

In this case in the reactants side we have 3 C, 8 H and 10 O, so we have  the same amount in the product side, so the equation is balanced.

In the equation Xe + F₂ → XeF₄ we have 1 Xe in each side, 2 F in the reactant side and 4 F in the product side, so we multiply the 2 F in reactan side to balance the equation.

Xe + 2Fe₂ → XeF₄

Ivahew [28]3 years ago
3 0

There are four F atoms on the products side.

Since two more F atoms are required on the reactant side, you multiply the number of F2 molecules by two.

So 2 should be placed in front of F2

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Answer:

7ml/g

Explanation:

density=mass/volume

density=14g/2ml

density= 7g/ml

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7 0
3 years ago
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Different vinegars can be 5-20% acetic acid solutions and have been used for medicinal purposes for thousands of years. If a per
nata0808 [166]

Answer:

1.5g

Explanation:

Remember that Molarity = (#moles of solute)/(#liters of solution)

This problem informs us that the Molarity of the vinegar is 0.84 and that the solution is 15mL.

First let's get your SI units to the correct ones.

15mL (1L/1000mL) = 0.015L

Molarity = (#moles of solute)/(#liters of solution) ~

(Molarity)(#liters of solution) = #moles of solute

(0.84M)(.015L) = 0.0126moles of acetic acid per tablespoon

2 tablespoons a day = 0.0126moles*2 =  0.0252 moles of acetic acid.

Now that we have the # of moles of acetic acid we need to get our answer into grams. The molecular weight of HC2H3O2 is 60g/mole.

0.0252mole HC2H3O2 (60g HC2H3O2/1mole HC2H3O2) = 1.512g ~ 1.5g HC2H3O2.

8 0
3 years ago
Which law relates temperature, pressure, volume, and the number of moles of a gas under perfect conditions? Boyle's law Charles'
Triss [41]
<span>The correct answer is ideal gas law.

when the ideal gas law formula is:

 PV = nRT ,

when P is the pressure. 

V is the volume. 

and R is the ideal gas constant.

T is the temperature. 

and n is the number of moles.

So, this is the law which relates pressure, temperature, volume and number of moles . and this law state that 1 mole of an ideal gas will occupy a volume V = 22.4 L</span>
6 0
3 years ago
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2.00 L of 0.800 M NaNO3 must be prepared from a solution known to be 2.50 M in concentration.How many mL are required? Plus don'
Morgarella [4.7K]

Answer:

1.36 × 10³ mL of water.

Explanation:

We can utilize the dilution equation. Recall that:

\displaystyle M_1V_1= M_2V_2

Where <em>M</em> represents molarity and <em>V</em> represents volume.

Let the initial concentration and unknown volume be <em>M</em>₁ and <em>V</em>₁, respectively. Let the final concentration and required volume be <em>M</em>₂ and <em>V</em>₂, respectively. Solve for <em>V</em>₁:

\displaystyle \begin{aligned} (2.50\text{ M})V_1 &= (0.800\text{ M})(2.00\text{ L}) \\ \\ V_1 & = 0.640\text{ L} \end{aligned}

Therefore, we can begin with 0.640 L of the 2.50 M solution and add enough distilled water to dilute the solution to 2.00 L. The required amount of water is thus:
\displaystyle 2.00\text{ L} - 0.640\text{ L} = 1.36\text{ L}

Convert this value to mL:
\displaystyle 1.36\text{ L} \cdot \frac{1000\text{ mL}}{1\text{ L}} = 1.36\times 10^3\text{ mL}

Therefore, about 1.36 × 10³ mL of water need to be added to the 2.50 M solution.

8 0
2 years ago
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