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Sedaia [141]
3 years ago
15

which number should be placed before F2 on the reactants side equation to make equation balanced? Xe + ___F2 > XeF4

Chemistry
2 answers:
jolli1 [7]3 years ago
5 0

Answer:

The number that should be placed before F₂ is 2

Explanation:

For a chemical reaction to be balanced we need to have the same amount of mass in the reactants and in the products because by the<em> law of conservation of mass</em>, mass cannot be created or destroyed.

We can acomplish this by having the same amount of atoms of each element in the reactant side that in the product side.

For example:

C₃H₈ + 5O₂ → 3CO₂ + 4H₂0

In this case in the reactants side we have 3 C, 8 H and 10 O, so we have  the same amount in the product side, so the equation is balanced.

In the equation Xe + F₂ → XeF₄ we have 1 Xe in each side, 2 F in the reactant side and 4 F in the product side, so we multiply the 2 F in reactan side to balance the equation.

Xe + 2Fe₂ → XeF₄

Ivahew [28]3 years ago
3 0

There are four F atoms on the products side.

Since two more F atoms are required on the reactant side, you multiply the number of F2 molecules by two.

So 2 should be placed in front of F2

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What is the name of an ideal-gas process in which no heat is transferred?.
PIT_PIT [208]

Answer:

Adiabatic. This is a process where no heat is being added or removed from the system. Or can be simply stated as: no heat transfer (or heat flow) happening in a system.

Explanation:

6 0
2 years ago
What is the molarity of solution obtained when 5.71 g of sodium carbonate-10-water is dissolved in water and made up to 250.0 cm
disa [49]

We have to know the molarity of solution obtained when 5.71 g of Na₂CO₃.10 H₂O is dissolved in water and made up to 250 cm³ solution.

The molarity of solution obtained when 5.71 g of sodium carbonate-10-water (Na₂CO₃.10 H₂O)  is dissolved in water and made up to 250.0 cm^3 solutionis: (A) 0.08 mol dm⁻³

The molarit y of solution means the number of moles of solute present in one litre of solution. Here solute is Na₂CO₃.10 H₂O and solvent is water. Volume of solution is 250 cm³.

Molar mass of Na₂CO₃.10 H₂O is 286 grams which means mass of one mole of Na₂CO₃.10 H₂O is 286 grams.

5.71 grams of Na₂CO₃.10 H₂O is equal to \frac{5.71}{286}= 0.0199 moles of Na₂CO₃.10 H₂O. So, 0.0199 moles of Na₂CO₃.10 H₂O present in 250 cm³ volume of solution.

Hence, number of moles of Na₂CO₃.10 H₂O present in one litre (equal to 1000 cm³) of solution is \frac{0.0199 X 1000}{250} = 0.0796 moles. So, the molarity of the solution is 0.0796 mol/dm³ ≅ 0.08 mol/dm³


3 0
3 years ago
A chemical reaction that has the general formula of nA ➡ (A)n is best classified as a ___________ reaction
tekilochka [14]
The answer to this question is sodium
8 0
3 years ago
Read 2 more answers
3. How many atoms in 3.91 moles of sodium?
Gala2k [10]

Answer:

Explanation:

The formula for sodium is Na. It does not form a molecule in some way.

1 mol Na = 6.02*10^23 atoms

3.91 mol = x                                    Cross multiply

x = 3.91 * 6.02 * 10^23

x = 23.65 * 10^23

x = 2.365 * 10^24

Scientific notation is always expressed as a number 1 ≤ x < 10

3 0
3 years ago
How many moles of solute are in 53.1 mL of 12.5M HCI?
Deffense [45]
Molarity = moles of solute/volume of solution in liters.

From this relation, we can figure out the number of moles of solute by multiplying the molarity of the solution by the volume in liters.

We have 53.1 mL, or 0.0531 L, of a 12.5 M, or 12.5 mol/L, solution. Multiplying 12.5 mol/L by 0.0531 L, we obtain 0.664 moles. So, in this volume of solution, there are 0.664 moles of solute (HCl).
6 0
2 years ago
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