Question

. A sample of crude oil has a density of 0.87 g/mL. What volume (in liters) does a 3.6 kg sample of this oil occupy

Answer 1

Answer:

The volume is 4.13793 L

Explanation:

Density is a quantity that expresses the relationship between the mass and the volume of a body, so it is defined as the quotient between the mass and the volume of a body:

$density=\frac{mass}{volume}$

Density is a characteristic property of every body or substance.

The most commonly used units of density are $\frac{kg}{m^{3} }$ or $\frac{g}{cm^{3} }$ for solids, and $\frac{kg}{L}$ or $\frac{g}{mL}$ for liquids and gases.

In this case, you know:

• density= 0.87 $\frac{g}{mL}$
• mass= 3.6 kg= 3,600 g (being 1 kg=1,000 g)
• volume= ?

Replacing:

$0.87\frac{g}{mL} =\frac{3,600 g}{volume}$

Solving:

$volume =\frac{3,600 g}{0.87\frac{g}{mL}}$

volume= 4,137.93 mL

Being 1,000 mL=1 L, then volume= 4,137.93 mL= 4.13793 L

The volume is 4.13793 L