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liubo4ka [24]
3 years ago
5

Express your answer as a chemical equation. Identify all of the phases in your answer. Enter noreaction if no precipitate is for

med.A) liquid pentanol (C5H12O) and gaseous oxygenB) aqueous ammonium chloride and aqueous calcium hydroxideC)aqueous strontium sulfide and aqueous copper(II) sulfate
Chemistry
1 answer:
liubo4ka [24]3 years ago
6 0

Answer:

A) C₅H₁₂O(l) + 7.5 O₂(g) → 5 CO₂(g) + 6 H₂O(l)

B) No reaction

C) SrS(aq) + CuSO₄(aq) → CuS(s)↓ + SrSO₄(aq)

Explanation:

<em>A) liquid pentanol (C₅H₁₂O) and gaseous oxygen.</em>

This is a combustion reaction. assuming the combustion is complete, the products are CO₂ and H₂O.

C₅H₁₂O(l) + 7.5 O₂(g) → 5 CO₂(g) + 6 H₂O(l)

<em>B) aqueous ammonium chloride and aqueous calcium hydroxide.</em>

We could expect a double displacement reaction to take place. But since the products are CaCl₂ and NH₄OH, both of them soluble, no reaction occurs.

<em>C)aqueous strontium sulfide and aqueous copper(II) sulfate.</em>

This is a double displacement reaction. The formed precipitate is CuS.

SrS(aq) + CuSO₄(aq) → CuS(s)↓ + SrSO₄(aq)

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A 265-mL flask contains pure helium at a pressure of 751 torrs. A second flask with a volume of 465 mL contains pure argon at a
Nadya [2.5K]

Answer:

Total Pressure = 745.6 torr

Partial Pressure of He = 272.8 torr

Partial Pressure of Ar =  472.8 torr

Explanation:

Step 1: Data given

Volume of the flask helium = 265 mL

Pressure in the helium flask = 751 torr = 751/760 atm

Volume of the flask argon = 465 mL

Pressure in the argon flask = 727 torr = 727/760 atm

The total pressure exerted by a gaseous mixture is equal to the sum of the partial pressures of each individual component in a gas mixture.

Step 2: Calculate total volume

Total volume = 265 mL + 465 mL = 730 mL =  0.730 L

Step 3: Boyle's Law:

P1V1=P2V2

⇒ with P1 = total pressure gas exerts in its own flask

 ⇒ with V1 = volume of flask with stopcock valve closed

 ⇒ with P2 = partial pressure of gas exerts on total volume of both flasks when stopcock valve is opened  

 ⇒ with V2 = total volume of both flasks with stopcock valve opened

Helium using Boyle's Law equation from above:

P1V1=P2V2

⇒ with P1 = Pressure of helium = 751 /760 = 0.98816 atm

 ⇒ with V1 = volume of helium = 0.265 L

 ⇒ with P2 = The new partial pressure of helium

 ⇒ with V2 = total volume = 0.730 L

(0.98816 atm)(0.265L)=P2(0.730L)

P2=0.359 atm

Argon using Boyle's Law equation from above:

P1V1=P2V2

⇒ with P1 = Pressure of argon = 727/760 = 0.95658 atm

 ⇒ with V1 = volume of argon = 0.465 L

 ⇒ with P2 = The new partial pressure of argon

 ⇒ with V2 = total volume = 0.730 L

(0.95658 atm)(0.465L)=P2(0.730L)

P2=0.609 atm

Step 4: Convert pressure in atm to torr

Pressure helium = 0.359 atm = 272.8 torr

Pressure argon = 0.609 atm = 472.8 torr

Step 5: Calculate Total pressure

Ptotal = P(He)+P(Ar)

⇒ Pt  = total pressure of the gas mixture

⇒ P(He) = partial pressure of Helium

 ⇒ P(Ar)  = partial pressure of Argon

Pt = 272.8 torr + 472.8 torr

Pt = 745.6 torr

Total Pressure = 745.6 torr

Partial Pressure of He = 272.8 torr

Partial Pressure of Ar =  472.8 torr

5 0
4 years ago
Which order is correct in listing the bond lengths from shortest to longest? A. single, double, triple B. triple, double, single
Alex787 [66]
A I believe would be the answer
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4 years ago
How many grams are in 5.00 moles of sodium carbonate?
dimulka [17.4K]

Answer:

= 529.9422

grams

Explanation:

5  moles Sodium Carbonate

= 529.9422

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3 years ago
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Forward reaction equals the rate of the backward reaction
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What is the basis for the classification of changes in matter into physical and chemical changes quizlet
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Explanation:

The basis for classifying changes in matter into physical and chemical change is to see if a material is altered after going through a process.

In a physical change only the state of matter is usually altered especially its form or shape.

Chemical change alters a substance by producing new kinds that are totally different from it.

  • In  a chemical change, new kinds of matter are usually formed.
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