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tatiyna
3 years ago
8

Use a sheet of paper to answer the following question. Take a picture of your answers and attach to this assignment. Draw the st

ructure of 2,2,4,4-tetramethyl-3-pentanone and explain why it does not form an enol tautomer Explain why cyclohexa-2,4-dien-1-one (also called 2,4-cyclohexadienone) exists exclusively in the enol form

Chemistry
1 answer:
pentagon [3]3 years ago
8 0

Answer:

Explanation:

Structure of the 2,2,4,4-tetramethyl-3-pentanone is give in the attachment

In 2,2,4,4-tetramethyl-3-pentanone, no alpha hydrogen is present, therefore, enol form is not possible and hence, exist only in keto form.

Explanation for existence of cyclohexa-2,4-diene-1-one only in enol form:

keto form of cyclohexa-2,4-diene-1-one not aromatic and hence less stable.

Whereas enol form it is aromatic which makes it highly stable. that's why cyclohexa-2,4-diene-1-one exists only in enol form.

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A sample of a substance has a volume of 60.5ml and a density of 1.20g/ml what is density of magneis
erica [24]

Answer:

m = 72.6 grams

Explanation:

Given that,

The density of the substance uis 1.2 g/mL

Volume, V = 60.5 mL

We need to find the mass of the substance. Density is equal to mass divided by its volume. So, it can be given by :

d=\dfrac{m}{V}\\\\m=d\times V\\\\m=1.2\ g/mL\times 60.5\ mL\\\\m=72.6\ g

So, the mass of the substance is 72.6 grams.

8 0
3 years ago
Which of the following liquids or solutions, at the same concentration, will have the lowest freezing point and why?
jok3333 [9.3K]

Answer:idk

Explanation:Idk

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3 years ago
Consider the energy diagram below.
bagirrra123 [75]
It is A because it has a lower activation emery than like B
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3 years ago
Read 2 more answers
1-butanol yields 1-bromobutane in the presence of concentrated sulfuric acid and an excess of sodium bromide. CH3CH2CH2CH2OH (l)
Zanzabum

Answer:

The answer to your question is: yield = 56.27%

Explanation:

Data

             CH3CH2CH2CH2OH (l) → CH3 CH2CH2CH2Br

                18.54 ml 1-butanol            15.65 g of 1-bromobutane

% yield = ?

density = 0.81 g/ml

MM = 74 g  1- butanol

MM = 137 g 1-bromobutane

Process

Calculate mass of 1- butanol

              density = mass/volume

              mass = density x volume

              mass = 0.81 x 18.54

              mass = 15.02 g of 1-butanol

Theoretical yield

              74 g of 1- butanol -----------------  137 g of 1-bromobutane

              15.02 g of 1- butanol -------------   x

              x = (15.02 x 137) / 74

              x = 27.81 g of 1-bromobutane

% yield = experimental yield / theoretical yield x 100

% yield = 15.65 / 27.81 x 100

% yield = 56.28

6 0
4 years ago
What is the pressure of a gas in torr if its pressure is 305 kPa?
FromTheMoon [43]

Answer:

the pressure of the gas in torr is 2280 torr

Explanation:

The pressure of a gas in torr can be calculated by converting its pressure in kPa to atmospheres and then converting the atmospheric pressure to torr.

One atmosphere is equal to 101.325 kPa. Therefore, the pressure of the gas in atmospheres is 305 kPa / 101.325 kPa/atm = 3.00 atm.

One torr is equal to 1/760 of an atmosphere. Therefore, the pressure of the gas in torr is 3.00 atm * 760 torr/atm = 2280 torr.

Therefore, the pressure of the gas in torr is 2280 torr

3 0
2 years ago
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