Answer:
537.68 torr.
Explanation:
- We can use the general law of ideal gas:<em> PV = nRT.</em>
where, P is the pressure of the gas in atm.
V is the volume of the gas in L.
n is the no. of moles of the gas in mol.
R is the general gas constant,
T is the temperature of the gas in K.
- If n and V are constant, and have different values of P and T:
<em>(P₁T₂) = (P₂T₁).</em>
P₁ = 485 torr, T₁ = 40°C + 273 = 313 K,
P₂ = ??? torr, T₂ = 74°C + 273 = 347 K.
∴ P₂ = (P₁T₂)/(P₁) = (485 torr)(347 K)/(313 K) = 537.68 torr.
water vapor>liquid water> ice is the correct order of increasing standard molar entropy.
Since water has more entropy than ice, melting is encouraged by entropy. However, ice has less energy than water, which means that energy favors freezing. The distinction between liquid water, ice, and water vapor is that each of them is a different state of matter. Ice represents the solid state, liquid water the liquid state, and water vapor the gaseous state of water. As a result, the system's entropy reduces. A vapour condensing is an exothermic process. Consequently, the environment's entropy rises. however, the environment's growth in entropy grows. Since the gas state has a higher entropy than the liquid state does, the entropy change for the vaporization of water is positive.
Learn more about entropy here-
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Answer: (c)
Explanation:
Nuclear fusion reactions involve 2 smaller nuclides combining to form one larger nuclide.
However, the mass is not correctly balanced for (a), but it is for (c).
Answer:
The jewelry is 2896.54_Kg/m^3 less dense than pure silver
Explanation:
Density of jewellery = (mass of jewellery) ÷ (volume of jewellery)
=3.25g ÷ 0.428mL = 0.00325Kg÷0.000000428m^3 = 7583.46Kg/m^3
The density of silver is 10490_Kg/m^3 which is (10490 - 7583.46) 2896.54_Kg/m^3 more dense than the jewellery
The density of Silver [Ag]
The weight of Silver per cubic centimeter is 10.49 grams or the weight of silver per cubic meter is 10490 kilograms, that is the density of silver is 10490 kg/m³; at 20°C (68°F or 293.15K) at a pressure of one atmospheres.