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Gnesinka [82]
3 years ago
12

Which is the same length as a light-year?

Chemistry
2 answers:
Ilya [14]3 years ago
7 0
A the distance light travels in one year is the correct answer I took the test
andrew11 [14]3 years ago
5 0

Answer:

A

Explanation:

Just A...

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A gardener waters the plants in a garden using a garden hose during a drought. The gardener observes that most of the water give
Anna71 [15]

Answer:

Break up the soil to increase the number of pores should be your answer.

Explanation:

If you do that it will increase the amount of water in the plant.

8 0
3 years ago
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Ozone (O 3) is made of three atoms of oxygen. It is _
kykrilka [37]
An element I think maybe
3 0
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A 4.36-g sample of an unknown alkali metal hydroxide is dissolved in 100.0 mL of water. An acid-base indicator is added, and the
BARSIC [14]

Answer:

Rb+

Explanation:

Since they are telling us that the equivalence point was reached after 17.0 mL of   2.5 M HCl were added , we can calculate the number of moles of HCl which neutralized our unknown hydroxide.

Now all the choices for the metal cation are monovalent, therefore the general formula for our unknown is XOH and  we know the reaction is 1 equivalent acid to 1 equivalent base. Thus we have the number of moles, n,  of XOH and from the relation n = M/MW we can calculate the molecular weight of XOH.

Thus our calculations are:

V = 17.0 mL x 1 L / 1000 mL = 0.017 L

2.5 M HCl x 0.017 L = 2.5 mol/ L x 0.017 L = 0.0425 mol

0.0425 mol = 4.36 g/ MW XOH

MW of XOH = (atomic weight of X + 16 + 1)

so solving the above equation we get:

0.0425 = 4.36 / (X + 17 )

0.7225 +0.0425X = 4.36

0.0425X = 4.36 -0.7225 = 3.6375

X = 3.6375/0.0425 = 85.59

The unknown alkali is Rb which has an atomic weight of 85.47 g/mol

6 0
3 years ago
Describe the mass of the reactants and products given the balanced chemical reaction.
Andru [333]

Answer:

The mass of the reactants equals the mass of the products.

5 0
3 years ago
A gas has a volume of 543 ml. at a temperature of 75.0°C. What volume will the gas occupy at 20.2°C?
alexandr1967 [171]

Answer:

V₂ = 457.49 mL

Explanation:

Given that,

Initial volume, V_1=543\ mL

Initial temperature, T_1=75^{\circ} C=75+273=348\ K

Final temperature, T_2=20.2^{\circ} C=20.2+273=293.2\ K

We need to find the final volume of the gas. The relation between the volume and the temperature of the gas is given by :

\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}

Put the respected values,

V_2=\dfrac{V_1T_2}{T_1}\\\\V_2=\dfrac{543\times 293.2}{348}\\\\V_2=457.49\ mL

So, the final volume of the gas is equal to 457.49 mL.

5 0
3 years ago
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