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3 years ago

Which is the same length as a light-year?

Chemistry

2 answers:

Ilya [14]3 years ago

7 0

A the distance light travels in one year is the correct answer I took the test

andrew11 [14]3 years ago

5 0

Answer:

Explanation:

Just A...

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What is a concave structure

Bess [88]

A concave surface, structure, or line. tr.v. con·caved, concaving, con·caves.
hope that helped

6 0

3 years ago

How have observations in the sky enabled humans to explore and travel?

andre [41]

Answer:

Observations of the sky allowed explorers to mark the passage of time both in hours and through the months of the year. Early astronomers also realized that the night sky does not look the same from different places on the Earth.

4 0

3 years ago

`You have to be careful about pouring drano down your pipes since it is mainly hydrochloric acid--you can't do it if they are ma

notsponge [240]

Answer: The number of moles of hydrogen gas that will be produced is 15.0 moles.

Explanation:

We are given:

Moles of aluminum needed to be dissolved = 10.0 moles

For the given chemical reaction:

$2Al+6HCl\rightarrow 2AlCl_3+3H_2$

By Stoichiometry of the reaction:

2 moles of aluminium produces 3 moles of hydrogen gas

So, 10.0 moles of aluminium will produce = $\frac{3}{2}\times 10.0=15.0mol$ of hydrogen gas

Hence, the number of moles of hydrogen gas that will be produced is 15.0 moles.

8 0

3 years ago

**Find the speed of an object that travels 500 miles in 5 hours. S = d/t

irinina [24]

Answer:

I believe that would be 100 mph.

Explanation:

Your distance (d) is 500 miles and your time (t) is 5 hours.

So when you replace the variables with numbers you bet 500/5 which is 100.

Therefore, you speed (S) would be 100mph.

4 0

2 years ago

Chlorine gas can be prepared in the laboratory by the reaction of hydrochloric acid with manganese(IV) oxide.

lana66690 [7]

Answer:

a. HCl

b. 24.3 g of Cl₂

c. 19.4 g of Cl₂

Explanation:

a. In order to determine the limiting reactant we convert the mass of each reactant to moles.

The reaction is: 4HCl (aq) + MnO₂(s) → MnCl₂(aq) + 2H₂O (l) + Cl₂(g)

37.3 g / 86.94g/mol = 0.429 moles of manganese dioxide

50.1 g / 36.45 g/mol = 1.37 moles of HCl

Ratio is 1:4. 1 mol of MnO₂ needs 4 moles of hydrochloric to react

Then, 0.429 moles of dioxide will react with (0.429 . 4) /1 = 1.71 moles of HCl.

At least, we have 1.37 moles, so the HCl is the limiting reactant.

b. In this question, we can work with stoichiometry with a rule of three:

4 moles of HCl produce 1 mol of chlorine

Then, 1.37 moles of HCl will produce (1.37 . 1) /4 = 0.3425 moles of Cl₂

We convert the moles to mass → 24.3 g of Cl₂

c. In order to determine the actual yield of chlorine, we multiply

Theoretical yield . Yield percent/100 → 24.3 g . 79.9/100 = 19.4 g

3 0

3 years ago