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2 years ago

A gas cylinder contains exactly 15 moles of oxygen gas (O2) how many molecules of oxygen are in a cylinder

Chemistry

2 answers:

butalik [34]2 years ago

8 0

When you say mhello les do uou mean moecules

Tanzania [10]2 years ago

3 0

The answer is 9.03 × 1024<span> molecules hope it helps.</span>

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PLS HELP!I will give brainliest! When producing hydrogen iodide, the energy of the reactants is 581 kJ/mol, and the energy of th

Veronika [31]

Answer:

Here, we are required to determine the total energy of the reaction and determine if the reaction is an endothermic or exothermic reaction.

The correct answer is option C.

First, we need to determine the energy of the reaction.

The energy of the reaction is the change in enthalpy between the product and reactants.

Change of Enthalpy,

Hreaction = Hproduct - Hreactant.

Therefore, for the reaction above, the change in enthalpy is:

Hreaction = 590kJ/mol - 581kJ/mol.

Hreaction = 9kJ/mol.

Hence, since the reaction has an enthalpy change of 9kJ/mol, the reaction is endothermic (i.e energy is absorbed).

Explanation:

4 0

2 years ago

The part in the middle with a coil of wire wrapped around a metal shaft is part of an electric motor. What is it?

evablogger [386]

Answer:

rotor

Explanation:

The part of the motor being pointed to is called the <em>rotor</em>.

4 0

2 years ago

Read 2 more answers

plz answer 7 & 8 because I dont get the answer... oh and you need to use the picture for the questions 7 & 8 thanks

djyliett [7]

7. An exothermic reaction
8. The bonds are forming

4 0

3 years ago

Write a balanced half-reaction for the reduction of bismuth oxide ion to bismuth ion in basic aqueous solution. Be sure to add p

Butoxors [25]

Answer:

$3H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+6OH^-$

Explanation:

Hello there!

In this case, according to the required half-reaction, we start by setting it up from bismuth (V) oxide ion to bismuth (III) ion:

$BiO_3^-\rightarrow Bi^{3+}$

Thus, next realize that the oxidation state of Bi in BiO3^- is 5+ because oxygen is 2- (-2*3+x=-1;x=-1+6;x=+5), so we obtain:

$(Bi^{5+}O_3)^-\rightarrow Bi^{3+}$

Thereafter, we realize three water molecules are needed on the right in order to balance the oxygens and consequently 6 hydrogen atoms on the left to balance hydrogen:

$6H^++(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+3H_2O$

Now, since the balance is is basic media, we add six molecules of hydroxide ions in order to produce water with the hydrogen ones:

$6OH^-+6H^++(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+3H_2O+6OH^-\\\\6H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+3H_2O+6OH^-\\\\6H_2O-3H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+6OH^-$

Then, we accommodate the waters to obtain:

$3H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+6OH^-$

Best regards!

7 0

2 years ago

How many Liters of 0.50M HCl are needed to neutralize 0.050L of 0.101M Ba(OH)2?

Aleksandr-060686 [28]

Answer:

$V_{HCl}=5.05x10^{-3}L$

Explanation:

Hello,

In this case, since hydrochloric acid and barium hydroxide are in a 2:1 molar ratio, for the neutralization, the following moles equality must be obeyed:

$2*n_{HCl}=n_{Ba(OH)_2}$

In such a way, in terms of molarities and volumes, we can compute the required volume of hydrochloric acid as shown below:

$2*M_{HCl}V_{HCl}=M_{Ba(OH)_2}V_{Ba(OH)_2}\\\\V_{HCl}=\frac{M_{Ba(OH)_2}V_{Ba(OH)_2}}{2M_{HCl}} =\frac{0.101M*0.050L}{2*0.50M} \\\\V_{HCl}=5.05x10^{-3}L$

Besr regards.

8 0

2 years ago

Read 2 more answers