Answer:
16 g/L
Explanation:
Given that:-
Mass of sucrose added = 1.2 g
Volume of water = 75 mL = 0.075 L ( 1mL = 0.001 L )
%w/v is defined as the mass of the solution in 1 L of the solution.
So,


The concentration of [H3O+] will be 6.3 x
M
<h3>pH</h3>
Mathematically, pH = -log [H+] or -log [H3O+]
With a pH of 13.2:
-log [H3O+] = 13.2
log [H3O+] = -13.2
[H3O+] = 6.3 x
M
More on pH can be found here: brainly.com/question/491373
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I think it is rarefaction. But im not sure
There would be eighteen bonding electrons
Hello!
A) At pH=1
This pH is lower than the value for the pKa, so Acetic acid wouldn't be ionized, but the equilibrium would be displaced to
CH₃COOHCH₃COOH ⇄ CH₃COO⁻ + H₃O⁺ (equilibrium displaced to the
left)
The chemical structure for CH₃COOH is the first one in the attached images.
B) At pH=7
This pH is higher than the value for the pKa, so Acetic acid would be ionized, and the equilibrium would be displaced to
CH₃COO⁻
CH₃COOH ⇄ CH₃COO⁻ + H₃O⁺ (equilibrium displaced to the
right)
The chemical structure for CH₃COO⁻ is the second one in the attached images.
Have a nice day!