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Anna [14]
3 years ago
12

A hydrogen atom has a radius of 2.5 x 10^11m

Chemistry
2 answers:
Delvig [45]3 years ago
7 0
Ndhsjsjd
shhdhd
annandale
snhdhd
djd
g100num [7]3 years ago
4 0

Answer:

The radius of a Magnesium atom is (1.5).10^{-10}m

Explanation:

The question is wrong and a graph is missing.

It should be '' A hydrogen atom has a radius of (2.5).10^{-11}m ''

I also add the missing graph.

If we take a look at the graph, we can see that using that scale the atomic radius of the Hydrogen is 6mm and the atomic radius of Magnesium is 36mm

Therefore, the radius of the Magnesium atom

\frac{36mm}{6mm}=6

is six times bigger than the Hydrogen atom

If we multiply by 6 the radius of the Hydrogen atom ⇒

(6).(2.5).10^{-11}m=(1.5).10^{-10}m

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Mario uses a hot plate to heat a beaker of 50mL of water. He used a thermometer to measure the
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Mario uses a hot plate to heat a beaker of 50mL of water. He used a thermometer to measure the

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Using the molarity equation, calculate how many grams of salt you need in order to make 80ml of a 2M solution (MW = 58.44g/mole)
ollegr [7]

Answer:

9.35g

Explanation:

The molarity equation establishes that:

\textrm{molarity}=\frac{\textrm{moles  of solute}}{\textrm{liters of solution}}

So, we have information about molarity (2M) and volume (80 ml=0.08 l), with that, we can find the moles of solute:

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The  mathematical equation that establishes the relationship between molar weight, mass and moles is:

\textrm{molar weight}= \frac{\textrm{mass}}{\textrm{moles}}

\textrm{MW}= \frac{\textrm{m}}{\textrm{n}}

We have MW (58.44g/mole) and n (0.16 mol), and we need to find m (grams of salt needed) to solve the problem:

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