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elena-14-01-66 [18.8K]
3 years ago
14

a radiator is filled with a mixture of 3.25kg ethylene glycol (C2H6O2) in 7.75kg of water. calculate the molality of this questi

on
Chemistry
1 answer:
Vladimir [108]3 years ago
5 0
3.25 kg in g = 3.25 * 1000 = 3250 g

Molar mass C₂H₆O₂ =  62.0 g/mol

Mass solvent = 7.75 kg

Number of moles:

n = mass solute / molar mass

n = 3250  / 62.0 

n = 52.419 moles

Molality = moles of solute / kilograms of solvent

M = 52.419 / 7.75

M = 6.7637 mol/kg

hope this helps!
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Determine the empirical formula of the following compound if a sample contains 0.104 molK, 0.052 molC, and 0.156 molO;?
faltersainse [42]

Answer:

K₂CO₃    

Explanation:

Given parameters:

Number of moles of K = 0.104mol

Number of moles of C = 0.052mol

Number of moles of O = 0.156mol

Method

From the given parameters, to calculate the empirical formula of the elements K, C and O, we reduce the given moles to the simplest fraction.

Empirical formula is the simplest formula of a compound and it differs from the molecular formula which is the actual formula of a compound.

  • Divide the given moles through by the smallest which is C, 0.052mol.
  • Then approximate values obtained to the nearest whole number of multiply by a factor to give a whole number ratio.
  • This is the empirical formula

Solution

Elements                             K                       C                    O

Number of moles            0.104                0.052            0.156

Dividing by the

smallest                       0.104/0.052     0.052/0.052  0.156/0.052

                                            2                           1                     3

The empirical formula is K₂CO₃      

3 0
3 years ago
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