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3 years ago

If you can plz help ASAP Read the chemical equation.

Chemistry

1 answer:

Svetllana [295]3 years ago

6 0

N2 + 3H2 = 2NH3

in this question, we are dealing with only NH3 and H2 so we only focus on that

since the ratio of H2 to 2NH3 is 3:2, we say that

3 liters of H2 = 2 liters of 2NH3

3.6 litres of H2 = x liters of 2NH3

We cross multiple to give:

3 × x = 3.6 × 2

3x = 7.2

Divide both sides by 3

x = 7.2 ÷ 3

x = 2.4liters

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Which of these describes an endothermic reaction?

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Energy is absorbed bc endo means in so endothermic means energy is absorbed

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3 years ago

Josh drives her scooter 7 km north. she stops for lunch and then drives 5 km east. what distance does she cover? what was her di

weqwewe [10]

Explanation:

Find the motion diagram attached for the illustration:

Distance is the length of path traveled from the start to the finish. In measuring distance, we wall through the path from start to the finishing point. Distance is a scalar magnitude that has magnitude but no direction.

Displacement is distance that is taken between the start and finishing point. It is a vector quantity that has magnitude and measures direction.

To find the distance;

Distance = 5km + 7km = 12km

Displacement:

Using pythagoras theorem;

Displacement = √7² + 5² = 8.6km

Direction:

sin(bearing ) = $\frac{5}{8.6} = 0.5814$

bearing = arcSin 0.5814 = 035.6°

Displacement is 8.6km in a direction 035.6°

learn more:

Displacement brainly.com/question/6123316

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6 0

3 years ago

Please help me fast!!!

Dominik [7]

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3 0

3 years ago

How many moles of nitrogen are in 38 grams of nitrogen?

Lena [83]

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3 years ago

The electron in a hydrogen atom, originally in level n = 8, undergoes a transition to a lower level by emitting a photon of wave

timofeeve [1]

Explanation:

It is given that,

The electron in a hydrogen atom, originally in level n = 8, undergoes a transition to a lower level by emitting a photon of wavelength 3745 nm. It means that,

$n_i=8$

$\lambda=3745\ nm$

The amount of energy change during the transition is given by :

$\Delta E=R_H[\dfrac{1}{n_f^2}-\dfrac{1}{n_i^2}]$

And

$\dfrac{hc}{\lambda}=R_H[\dfrac{1}{n_f^2}-\dfrac{1}{n_i^2}]$

Plugging all the values we get :

$\dfrac{6.63\times 10^{-34}\times 3\times 10^8}{3745\times 10^{-9}}=2.179\times 10^{-18}[\dfrac{1}{n_f^2}-\dfrac{1}{8^2}]\\\\\dfrac{5.31\times 10^{-20}}{2.179\times 10^{-18}}=[\dfrac{1}{n_f^2}-\dfrac{1}{8^2}]\\\\0.0243=[\dfrac{1}{n_f^2}-\dfrac{1}{64}]\\\\0.0243+\dfrac{1}{64}=\dfrac{1}{n_f^2}\\\\0.039925=\dfrac{1}{n_f^2}\\\\n_f^2=25\\\\n_f=5$

So, the final level of the electron is 5.

4 0

3 years ago