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2 answers:
by angle sum property in traingle having
,
$50+70+x=180 \implies x=60^{\circ}$
now, by exterior angle property of triangle, $x+y=60+50$
put $x=60$ to get $y=50$
Here,
x+50°+70°= 180° [°.°Angle sum of triangle]
↪x= 180°-120°
↪x=60°
.°. x = 60°
Now,
Let z be the unknown angle of the second triangle
z+60°+50°=180° [°.° Angle sum of triangle ]
↪z=180°-110°
↪z=70°
. ° . z=70°
Then,
z+x+y= 180°
↪70°+60°+y=180°
↪y=180°-130°
↪y=50°
.°.y = 50°
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