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2 years ago

14

Which is an extraneous solution of the exponent x+sqrtx=6

1 answer:

zheka24 [161]2 years ago

3 0

First, we can simplify it down.
x = (-x + 6)^2
Then, you should have x - ( $x^{2}$ - 12x + 36).
Factor it to get x = 4 or 9. 4 works in the original equation but 9 does not.

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Fraction 3 over 4x = Fraction 1 over 5. x = ___?

umka21 [38]

Answer:

$\large\boxed{x=3\dfrac{3}{4}}$

Step-by-step explanation:

$\dfrac{3}{4x}=\dfrac{1}{5}\qquad\text{cross multiply}\\\\(4x)(1)=(3)(5)\\\\4x=15\qquad\text{divide both sides by 4}\\\\x=\dfrac{15}{4}\\\\x=3\dfrac{3}{4}$

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2 years ago

Read 2 more answers

If x=(10-3i) and y=(3-10i), then xy=? and x/y=?

Solnce55 [7]

Answer:

$xy=-109i$

$\frac{x}{y}=\frac{60}{109}+\frac{91}{109}i$

Step-by-step explanation:

$xy=(10-3i)(3-10i)$

To compute x times y must use foil on the right hand side.

First: $10(3)=30$

Outer: $10(-10i)=-100i$

Inner: $-3i(3)=-9i$

Last: $-3i(-10i)=30i^2=-30$

------------------------------------Add like terms:

$-109i$

----------------

$\frac{x}{y}$

$\frac{10-3i}{3-10i}$

Multiply top and bottom by bottom's conjugate:

$\frac{(10-3i)(3+10i)}{(3-10i)(3+10i)}$

Foil the top and just do first and last of Foil for the bottom since the bottom contains multiplying conjugates:

$\frac{30+100i-9i-30i^2}{9-100i^2}$

Replace $i^2$ with -1:

$\frac{30+91i+30}{9+100}$

$\frac{60+91i}{109}$

$\frac{60}{109}+\frac{91}{109}i$

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