All categories

3 years ago

Which is an extraneous solution of the exponent x+sqrtx=6

1 answer:

3 0

First, we can simplify it down.
x = (-x + 6)^2
Then, you should have x - ( $x^{2}$ - 12x + 36).
Factor it to get x = 4 or 9. 4 works in the original equation but 9 does not.

You might be interested in

Hilary Unraveled 3.0 centimeters of ribbon then continued to unravel 1.5 more centimeters. Which horizontal number line could be

Snezhnost [94]

<u>Answer:</u>

The horizontal number line that could be used to show number of centimeters of ribbon Hilary unraveled is 3cm to 4.5cm

<u>Explanation:</u>

Given that Hilary has already unraveled 3.0 centimeters of ribbon and then continues to unravel 1.5 more.

So starting will be 3.0 cm and maximum ribbon unravelled will be equal to 4.5cm so the horizontal number line that could be used would be from 3cm to 4.5cm including both fractional and integral values.

6 0

3 years ago

Read 2 more answers

Help me plss

Minchanka [31]

The quadratic formula is $y = ax^{2} +bx+ c$

$x^2-8x + 16 = 0\\(x-4)(x-4) = 0$

So the solution for k is 16.

Hope that helps!

8 0

2 years ago

Solve each equation by completing the square. n^2 - 6n + 6 = -2

Law Incorporation [45]

<h3><u>Explanation</u></h3>

Separate the constant out of expression.

$( {n}^{2} - 6n) + 6 = - 2$

Find the constant that makes the expression able to be squared. You have to subtract the separated constant by new constant as well.

$( {n}^{2} - 6n + 9) + 6 - 9 = - 2 \\ {(n - 3)}^{2} - 3 = - 2 \\ {(n - 3)}^{2} = 1$

Square Root both sides to get rid the squared expression. Make sure to write plus or minus.

$\sqrt{ {(n - 3)}^{2} } = + \sqrt{1} \\ \sqrt{ {(n - 3)}^{2} } = - \sqrt{1} \\ n - 3 = 1 \\ n - 3 = - 1$

$n - 3 = 1 \: \: \: or \: \: \: n - 3 = - 1 \\ n = 1 + 3 \: \: \: or \: \: \: n = - 1 + 3 \\ n = 4 \: \: \: or \: \: \: n = 2$

<h3><u>Answer</u></h3>

$\large \boxed {n = 4,2}$

3 0

3 years ago

Use the unit circle to find the inverse function value in degrees cos^-1 (sqrt3/2)

Marina CMI [18]

Better to write that as:

-1
cos [ sqrt(3) / 2 ]

since the cosine is defined as "adjacent side over hypotenuse," we know that the adj. side is sqrt(3) and that the hyp is 2. The primary solution will be in Quadrant I because the adj. side is positive.

Think: which angle in Q I has adj. side equal to sqrt(3) and hyp equal to 2?

That'd be 30 degrees. Unfortunately, that's not one of your answer choices. Thus, reflect that angle in the positive x-axis; you'll end up with a ray whose positive angle is 330 degrees.

I'd suggest you ensure that you've copied this problem down correctly.
sqrt(3)
Did you mean sqrt(3/2) or did you mean ---------- ??
2

3 0

3 years ago

May i get an answer? for 10 points

maria [59]

Answer:

$= 452.38 {cm}^{2} \\ \\$

Step-by-step explanation:

$area = 4\pi {r}^{2} \\ = 4 \times \pi \times 6 \times 6 \\ = 452.38 {cm}^{2}$

6 0

3 years ago

Read 2 more answers