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salantis [7]
2 years ago
9

The structure of an atom is defined by two numbers: the proton (atomic) number and the mass (nucleon) number. What is the electr

onic configuration of an atom with proton number 5 and mass number 11?
A 2,8,1
B 3,2
C 2,3
D 1,8,2​
Chemistry
1 answer:
zzz [600]2 years ago
3 0

Answer:

c

Explanation:

electronic configuration of  an atom with proton number 5 is 2, 3

since no. of proton = no. of electron

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3 years ago
Please help me with this
yaroslaw [1]

Answer:

3s orbital

Explanation:

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3 0
2 years ago
Read 2 more answers
Which statement best describes displacement? Check all that apply
Snowcat [4.5K]
ANSWER:
DISPLACEMENT IS THE SHORTEST PATH LENGTH COVERED BY AN OBJECT.
IT IS A VECTOR QUANTITY AS IT NEEDS BOTH DIRECTION AND MAGNITUDE TO MEASURE IT.
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3 0
2 years ago
If 27.3% of a sample of silver-112 decays in 1.52 hours, what is the half-life (in hours to 3 decimal places)?
ICE Princess25 [194]

<u>Answer:</u> The half life of the sample of silver-112 is 3.303 hours.

<u>Explanation:</u>

All radioactive decay processes undergoes first order reaction.

To calculate the rate constant for first order reaction, we use the integrated rate law equation for first order, which is:

k=\frac{2.303}{t}\log \frac{[A_o]}{[A]}

where,

k = rate constant = ?

t = time taken = 1.52 hrs

[A_o] = Initial concentration of reactant = 100 g

[A] = Concentration of reactant left after time 't' = [100 - 27.3] = 72.7 g

Putting values in above equation, we get:

k=\frac{2.303}{1.52hrs}\log \frac{100}{72.7}\\\\k= 0.2098hr^{-1}

To calculate the half life period of first order reaction, we use the equation:

t_{1/2}=\frac{0.693}{k}

where,

t_{1/2} = half life period of first order reaction = ?

k = rate constant = 0.2098hr^{-1}

Putting values in above equation, we get:

t_{1/2}=\frac{0.693}{0.2098hr^{-1}}\\\\t_{1/2}=3.303hrs

Hence, the half life of the sample of silver-112 is 3.303 hours.

6 0
3 years ago
How many grams of O₂ are required to react completely with 14.6 g of Na to form sodium oxide, Na₂O?
Bad White [126]

The balanced chemical reaction is :

O_2 + 4Na \ -> \ 2Na_2O

Number of moles of Na, n = \dfrac{14.6}{23} = 0.635 \  mol .

Now, from balance chemical reaction we can see that 1 mole of oxygen reacts with 4 moles of sodium.

So, number of moles of oxygen are :

n = \dfrac{0.635}{4}\  mole

So, amount of oxygen required is :

m = \dfrac{0.635 \times 32}{4}\  gm\\\\m = 5.08 \ gm

Therefore, 5.08 gram of oxygen will react with 14.6 gram of sodium.

7 0
2 years ago
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