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faltersainse [42]
3 years ago
8

The boiling point of ethanol is 78 °C. The molar heat(i.e., enthalpy)of vaporization of ethanol is 38.6 x 103J/mol. What is the

molar entropyof vaporization of ethanol?

Chemistry
1 answer:
kogti [31]3 years ago
4 0

Answer:

109.97JK-1

Explanation:

Entropy is the degree of disorderliness of a substance. It is given by ∆H/T where T is the absolute temperature in Kelvin.

Given ∆H= 38.6*10^3

T=78°C+ 273=351K

∆S=38.6*10^3/351=109.97JK-1 as shown the diagram.

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Zanzabum

Answer:

6.67 moles

Explanation:

Given that:-

Moles of hydrogen gas produced = 10.0 moles

According the reaction shown below:-

2Al + 6HCl\rightarrow 2AlCl_3 +3H_2

3 moles of hydrogen gas are produced when 2 moles of aluminium undergoes reaction.

Also,

1 mole of hydrogen gas are produced when \frac{2}{3} moles of aluminium undergoes reaction.

So,

10.0 moles of hydrogen gas are produced when \frac{2}{3}\times 10.0 moles of aluminium undergoes reaction.

<u>Moles of Al needed  = \frac{2}{3}\times 10.0 moles = 6.67 moles</u>

6 0
3 years ago
This is very urgent please hurry!!?!!??!
yawa3891 [41]

Answer:

The greatest acceleration when the unbalanced force is applied will be experienced in :

A) The box with a mass of 2 kg

Explanation:

According to second law of motion the external unbalanced force is directly proportional to rate of change of momentum.

F = (Final momentum - initial momentum)/time

or

Force is equal to the product of mass and acceleration

F = m x a

Here a= acceleration

m = mass of the object

If Force is constant then acceleration is inversely proportional to mass

a =\frac{F}{m}

A) The box with a mass of 2kg

F = 8 N

a =\frac{8}{2}

a = 4 m/s2

B) The box with the mass of 4kg

a =\frac{8}{4}

a = 2 m/s2

C) The box with a mass of 6kg

a =\frac{8}{6}

a = 1.33 m/s2

D) The box with a mass of 8kg

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3 0
4 years ago
Which alternative energy source would be expected to be the least dependent upon the weather?
Elza [17]
Of the three sources listed, geothermal energy 
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3 0
4 years ago
Read 2 more answers
What is the value for AG at 5000 K if AH = -220 kJ/mol and S= -0.05 kJ/(mol-K)?
Serhud [2]

Answer:

C. 30 kJ

Explanation:

Hello there!

In this case, in agreement to the thermodynamic definition of the Gibbs free energy, in terms of enthalpy of entropy:

\Delta G= \Delta H-T\Delta S

It is possible to calculate the required G by plugging in the given entropy and enthalpy as shown below:

\Delta G=-220kJ/mol-5000K*-0.05kJ/mol*K\\\\\Delta G=30kJ/mol

Therefore, the answer is C. 30 kJ .

Best regards!

4 0
3 years ago
This is very difficult
Oliga [24]

Answer: C

Explanation:

6 0
3 years ago
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