Answer:
196 gdm-3
Explanation:
There are two major units of concentration, moldm-3 and gdm-3. The first unit refers to molar concentration while the second unit refers to mass concentration. Both units are useful in chemistry when describing the concentration of solutions as deemed expedient in each particular case.
Here we are required to compute the mass concentration from the molar concentration. We must recall that; mass concentration= molar concentration × molar mass
Let us first obtain the molar mass of H2SO4 from the relative atomic masses given=
2(1) + 32 + 4(16) = 98 gmol-1
Molar concentration of H2SO4 = 2 moldm-3
Mass concentration= 2 moldm-3 × 98 gmol-1
Mass concentration = 196 gdm-3
The three situations can be described as
a) If we have two white powders and wish to distinguish between the two : the combinations can be sugar / salt or sugar / baking soda or salt / baking soda
all are kitchen items so we can either taste them
or in case of baking soda we can add it in water and it will produce brisk effervescence.
b) IF we have to distinguish in a given set of two transparent liquids which appear to be water (example water and vinegar)
we can identify them with the taste
we can identify them based on pH (vinegar will be acidic)
c) We have to find adulteration in a given sample of food
like adulteration in milk
for example presence of soap in milk
We can add indicator like phenolphthalein which will bring a pink colour in milk if soap is present
It would be:
B. HCl
A metal will react with an acid to form a salt (MgCl2) and H2.
The answer is 2) 4.7 g/mL because the solid use 17 mL and 80g/17mL is 4,7 g/mL.
I am assuming that the problem ask for the pressure in
the system. To be able to calculate this, we first assume that the system acts
like an ideal gas, then we can use the ideal gas equation to find for pressure
P.
P V = n R T
where,
P = Pressure (unknown)
V = 0.17 m^3
n = moles of lng / methane
R = gas constant = 8.314 Pa m^3 / mol K
T = 200 K
We find for the moles of lng. Molar mass of methane = 16
kg / kmol
n = 55 kg / 16 kg / kmol
n = 3.44 kmol CH4 = 3440 mol
Substituting all the values to the ideal gas equation:
P = 3440 mol * (8.314 Pa m^3 / mol K) * 200 K / 0.17 m^3
P = 33,647,247 Pa
<span>P = 33.6 MPa</span>
