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3 years ago

What is the perimeter of triangle with side lengths of 29, 15, and 4xy?

Mathematics

2 answers:

hoa [83]3 years ago

3 0

The perimeter of any polygon is equal to the sum of the length of all sides of this polygon.

Therefore:

olya-2409 [2.1K]3 years ago

3 0

Answer:

<h3><em>The perimeter of a triangle is defined as the sum of all three sides.</em></h3>

So, we know that sides are 29, 15 and 4xy long. The perimeter would be

$P=29+15+4xy$

Now, we sum like terms

$P=44+4xy$

<h3>Therefore, the perimeter of the triangle is</h3>

$P=44+4xy$

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How many groups of 2/3 are in 3/5

amid [387]

To find the answer, we will need to divide 3/5 by 2/3.

3/5 / 2/3

3/5 x 3/2

9 / 10

There are 9/10 groups of 2/3 in 3/5.

Hope this helps!! :)

5 0

2 years ago

(fog)(x). F(x)=3x, g(x)=x+7

ivann1987 [24]

For this case we have the following functions:

$f (x) = 3x\\g (x) = x + 7$

We must find $(f_ {0} g) (x)$ . By definition we have to:

$(f_ {0} g) (x) = f (g (x))$

So:

$f (g (x)) = 3 (x + 7) = 3x + 3 * 7 = 3x + 21$

Finally, the composite function is:

$(f_ {0} g) (x) = 3x + 21$

Answer:

$(f_ {0} g) (x) = 3x + 21$

4 0

3 years ago

PLEASE HELP ME <br> WILL AWARD BRAINLIEST

mixas84 [53]

Answer:

I think the answer is b

Step-by-step explanation:

there are the same number of squares in both shapes.

8 0

3 years ago

Read 2 more answers

PLEASE SOMEONE HELP

Yanka [14]

Infinity Many Solutions

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5 0

3 years ago

Determine the equation of the circle graphed below.

sergij07 [2.7K]

Answer:

Equation = (x - 6 )² + ( y + 3 )² = 9

Step-by-step explanation:

The circle passes through ( 6, 0) and ( 6 , -6)

They are the coordinates of the diameter.

Using this we can find the centre of the circle.

<u>Find the centre of the circle.</u>

Centre of the circle is the mid- point of (6, 0) and ( 6, -6)

$Centre = (\frac{x_1+x_2}{2} , \frac{y_1 + y_2}{2})$

$=(\frac{6 + 6}{2}, \frac{0 + (-6)}{2})\\\\=(6, -3)$

<u>Find the radius of the circle.</u>

$Radius = \frac{Diameter }{2}$

Diameter is the distance between the points (6 , 0) and ( 6, - 6)

$Diameter = \sqrt{(x_2 - x_1)^2+ (y_2 - y_1)^2\\}$

$=\sqrt{(6-6)^2 + (-6 -0)^2}\\\\=\sqrt{0 + 36} \\\\= 6$

Therefore,

$Radius ,r = \frac{6}{2} = 3$

<u>Standard equation of a circle:</u>

<u></u> $(x - a)^2 + (y - b)^2 = r^2 \ where \ (a , b) \ is \ the\ centre \ coordinates.$ <u></u>

Therefore , equation of the circle ;

$(x - 6)^2 + (y + 3)^2 = 3^2\\\\(x -6)^2 + (y + 3)^2 = 9$

6 0

3 years ago