What is the perimeter of triangle with side lengths of 29, 15, and 4xy?

Mathematics

2 answers:

hoa [83]3 years ago

3 0

The perimeter of any polygon is equal to the sum of the length of all sides of this polygon.

Therefore:

olya-2409 [2.1K]3 years ago

3 0

Answer:

<h3><em>The perimeter of a triangle is defined as the sum of all three sides.</em></h3>

So, we know that sides are 29, 15 and 4xy long. The perimeter would be

$P=29+15+4xy$

Now, we sum like terms

$P=44+4xy$

<h3>Therefore, the perimeter of the triangle is</h3>

$P=44+4xy$

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A rectangle has a length of 45 inches less than 4 times its width. if the area of the rectangle is 3325 square inches, find the

Maru [420]

The length of the rectangle is based on its width, so let's call width w and put the length in terms of the width. We are told that the width is 45 less than 4 times the width, so the length is 4w - 45. Area is found by multiplying length times width and we are given the area as 3325. So we will set up length times width and solve for w, which we will then use to solve for l. 3325 = (4w - 45)(w). Multiplying out we have $3325=4w^2-45w$ . Move the constant over by subtraction and then we will have a quadratic that can be factored to solve for w. $4w^2-45w-3325=0$ . We would put that through the quadratic formula to solve for w. When we do that we get that w = 35 and w = -23.75. The 2 things in math that will never EVER be negative is time and distance/length, so -23.75 is out. That means that the width is 35. The length is 4(35) - 45 which is 95. The dimensions of your rectangle are length is 95 and width is 35. There you go!