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spin [16.1K]
3 years ago
15

Which statements about the ellipse are true? Check all

Mathematics
1 answer:
san4es73 [151]3 years ago
4 0

Answer:the answer is 1,2,4,and5

Step-by-step explanation:

Just took the assignment hope this helps:)

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-3/5m + 8 = 20<br> what is the answer of m
horrorfan [7]

\qquad\qquad\huge\underline{{\sf Answer}}♨

Let's solve ~

\qquad \sf  \dashrightarrow \:  - \frac{  3}{5} m + 8 = 20

\qquad \sf  \dashrightarrow \:  - \frac{  3}{5} m  = 20 - 8

\qquad \sf  \dashrightarrow \:  - \frac{  3}{5} m  =12

\qquad \sf  \dashrightarrow \:  - \frac{  }{} m  =12 \times  \frac{5}{3}

\qquad \sf  \dashrightarrow \: - m = 4 \times 5

\qquad \sf  \dashrightarrow \:m =  - 20

➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖

8 0
3 years ago
Divide. (3 3/4)÷(−2 1/2) Enter your answer as a mixed number, in simplified form, in the box.
neonofarm [45]
3 \frac{3}{4} = \frac{15}{4}

Because (4*3) + 3 = 15. Similary find the improper fraction for -2 1/2.

(15/4) / (-5/2) = -3/2

Convert -3/2 into a mixed fraction. 

Therefore, -3/2 = -1 1/2.
6 0
3 years ago
Read 2 more answers
Find the value of x.
miss Akunina [59]

Answer:

x = 26

Step-by-step explanation:

The sum of the 3 angles in a triangle = 180°

Sum the given angles and equate to 180

55 + 4x - 5 + x = 180, that is

50 + 5x = 180 ( subtract 50 from both sides )

5x = 130 ( divide both sides by 5 )

x = 26

4 0
3 years ago
Kaylee is selling candles to raise money for her lacrosse team. The large candles sell for $25 each and the small
EastWind [94]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the following :

Cost of large candle (a) = 25 each

Cost of small candles (y) = 10 each

Amount needed = $600

Number of each that must be sold to raise needed amount:

25a + 10y = 600.

Here a = number of large candles that must be sold at the price

y = number of small candles that must be sold at the price

Summing the revenue both should result in the required amount.

5 0
3 years ago
Solve quadratic formulax^2-4x+3=0
bekas [8.4K]

The general formula for a equation of the form:

ax^2+bx+c=0

is:

x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}

In this case we notice that a=1, b=-4 and c=3. Plugging this values in the general formula we get:

\begin{gathered} x=\frac{-(-4)\pm\sqrt[]{(-4)^2-4(1)(3)}}{2(1)} \\ =\frac{4\pm\sqrt[]{16-12}}{2} \\ =\frac{4\pm\sqrt[]{4}}{2} \\ =\frac{4\pm2}{2} \end{gathered}

then:

x_1=\frac{4+2}{2}=\frac{6}{2}=3

and

x_2=\frac{4-2}{2}=\frac{2}{2}=1

Therefore, x=3 or x=1.

8 0
1 year ago
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