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jek_recluse [69]
3 years ago
15

678908256710x92739382

Mathematics
1 answer:
Lemur [1.5K]3 years ago
4 0

Answer: 6.2961532e+19

<h3>Step-by-step explanation:---there are too many numbers but this was my result I hope it helps you--</h3>

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PLeAsE i NeEd HeLp!!!!
olya-2409 [2.1K]

Answer:

<em>DF = 10 units</em>

m\angle DFG = 28^\circ

<em>EG = 5.04</em>

Step-by-step explanation:

<u>Properties of Rhombus es</u>

  1. All Sides Of The Rhombus Are Equal.
  2. The Opposite Sides Of A Rhombus Are Parallel.
  3. Opposite Angles Of A Rhombus Are Equal.
  4. In A Rhombus, Diagonals Bisect Each Other At Right Angles.
  5. Diagonals Bisect The Angles Of A Rhombus.

The image contains a rhombus with the following data (assume the center as point O):

DO = 5 units

GF = 5.6 units

m\angle FEO = 62^\circ

4. Calculate DF

Applying property 4, diagonals bisect each other, thus the length of DF is double the length of DO, i.e. DF=2*5 = 10:

DF = 10 units

5. Calculate m\angle DFG

Applying property 4 in triangle EFO, the center angle is 90°, thus angle EFO has a measure of 90°-62°=28°.

Applying property 5, this angle is half of the measure of angle EFG and angle DFG has the same measure of 28°.

m\angle DFG = 28^\circ

6. FG is the hypotenuse of triangle OFG, thus:

OG^2=FG^2-OF^2

OG^2=5.6^2-5^2

OG^2=6.36

OG=\sqrt{6.36}=2.52

EG is double OG: OG=2*2.52=5.04

EG = 5.04

5 0
2 years ago
Simplify your answer as much as possible
loris [4]

9514 1404 393

Answer:

  -4u^2/y+(5/2)y^3u^2

Step-by-step explanation:

The applicable rules of exponents are ...

  (a^b)(a^c) = a^(b+c)

  (a^b)/(a^c) = a^(b-c)

__

  (8y^2u^7-5y^6u^7)\div(-2y^3u^5)=\dfrac{8y^2u^7-5y^6u^7}{-2y^3u^5}\\\\=-4y^{2-3}u^{7-5}+\dfrac{5}{2}y^{6-3}u^{7-5}=\boxed{\dfrac{-4u^2}{y}+\dfrac{5}{2}y^3u^2}

7 0
2 years ago
Pam likes to practice dancing while preparing for a math tournament. She spends 80 minutes every day practicing dance and math.
Kisachek [45]
80/2= 20 then take away the extra 20 from the math for dance and you have the answer... 20 get it?
8 0
3 years ago
Read 2 more answers
A business owner opens one store in town A. The equation p(x) = 10,000(1.075) represents the anticipated profit after t years. T
alexgriva [62]
The rigth equation to anticipate the profit after t years is p(t) = 10,000 (1.075)^t

So, given that both store A and store B follow the same equations but t is different for them, you can right:

Store A: pA (t)  10,000 (1.075)^t

Store B: pB(t'): 10,000 (1.075)^t'

=> pA(t) / pB(t') = 1.075^t / 1.075^t'

=> pA(t) / pB(t') = 1.075 ^ (t - t')

And t - t' = 0.5 years

=> pA(t) / pB(t') = 1.075 ^ (0.5) = 1.0368

or pB(t') / pA(t) = 1.075^(-0.5) = 0.964

=> pB(t') ≈ 0.96 * pA(t)

Which means that the profit of the store B is about 96% the profit of store A at any time after both stores have opened.


7 0
3 years ago
Read 2 more answers
Y=-4x+10 what is the y value of this equation
AveGali [126]

Answer:

y=5/2

Step-by-step explanation:

3 0
3 years ago
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