50 quarts of 5% butterfat and 1% butterfat milk are to be mixed.
<u>SOLUTION:
</u>
First, I will set up my table. I will fill in the unknowns with variables x and y.
The table is attached below
From the table attached below, we can easily set up the two equations.
<em>Sum of values of two milks = Value of mixture </em>
0.05x + 0.01y = 3
For convenience, we'll multiply the entire equation by 100,
5 x + y = 300 ------> (1)
Now, Sum of amounts of each acid = Amount of mixture
x + y = 100 ---------> (2)
Subtracting equation (2) from (1),
( + ) 5 x + y = 300
( − ) x - y = 100
− − − − − − − −
( = ) 4x + 0y = 200
Thus, 4x = 200
x = 50
Substituting x = 50 in (2),
( 50 ) + y = 100
y = 100 – 50 = 50
hence, 50 quarts of 5% butterfat and 1% butterfat milk are to be mixed.
Answer:
7(2+x)(2-x)
Step-by-step explanation:
Both terms are perfect squares,use the difference of square formulas
a^2-b^2=(a+b)(a-b) where a=2 and b=x
To calculate the percentage increase: First: work out the difference (increase) between the two numbers you are comparing. Then: divide the increase by the original number and multiply the answer by 100.
45-32 = 13 / 32 *100= 40.625 round to the nearest percent is 41%
Answer
7.21
Step-by-step explanation:
Data :
(-3,-4) , (1,2)
Where
x₁ = -3 , x₂ = 1
y₁ = -4 , y₂ = 2
Formula for distance
D = √{(x₂-x₁)² + (y₂-y₁)²}
= √{(l--3)² + (2--4)²} = √(16+36) =√52 =7.21