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Pepsi [2]
3 years ago
7

Is a gold necklace a element, compound, or a mixture

Chemistry
1 answer:
Akimi4 [234]3 years ago
3 0

Answer:

It would be an element my dear.

--------------------------------------------------------------------------------------------

Pure gold is an element. That is, it is not a combination of other materials. However, gold used in jewelry is usually a “mixture”, called an alloy mixed with other metals to harden it, to change the color as in copper makes the pink or rose gold that is currently enjoying great polarity.

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If I add 2.75 g of CaO to 155 mL of distilled water, what will be the concentration of the solution be?
IRINA_888 [86]
M = m/L
moles of CaO = 2.75g / molar mass
2.75g/ 56.08g = 0.049moles CaO
155mL / 1000 = 0.155 L
M= 0.049moles/0.155L
M=0.316
7 0
2 years ago
the red line observed in the line spectrum for hydrogen has 3.03x10^-19J, what is the wavelength, in nm, of this?
djverab [1.8K]

Answer:

λ = 6.5604 x 1016 nm

Explanation:

Given Data:

The energy of the red line in Hydrogen Spectra = 3.03 x 10-19

Formula to calculate Wave length

E= hv

Where E is Energy

h is Planks Constant = 6.626 x 10–34 J s

v is frequency

In turn

v= c/ λ

where c is speed of light = 3.00 x 108 m s–1

λ is wavelength = to find

Solution:

Formula to be Used:

E= hv………………………… (1)

Putting the value v in equation 1

               E= h c/ λ…………………… (2)

Put the value in equation 2

3.03 x 10-19 J  = (6.626 x 10–34 J s) x (3.00 x 108 m s–1) / λ ……………………….(3)

By rearranging equation 3

λ = (6.626 x 10–34 J s) x (3.00 x 108 m s–1) /3.03 x 10-19  J

λ = 6.5604 x 107 m

The answer is in “m”

So we have to convert it into nm

So for this to convert “m” to “nm” multiply the answer with 109

λ = 6.5604 x 107 x 109

λ = 6.5604 x 1016 nm

6 0
3 years ago
A total of 25.0 mL of 0.150 M potassium hydroxide (KOH) was required to neutralize 15.0 mL of sulfuric acid (H2SO4) of unknown c
Kamila [148]
We are told that KOH is being used to completely neutral H₂SO₄ according to the following reaction:

KOH + H₂SO₄ → H₂O + KHSO₄

If KOH can completely neutralize H₂SO₄, then there must be an equal amount of moles of each as they are in a 1:1 ratio:

0.025 L x 0.150 mol/L = .00375 mol KOH

0.00375 mol KOH x 1 mole H₂SO₄/1 mole KOH = 0.00375 mol H₂SO₄

We are told we have 15 mL of H₂SO₄ initially, so now we can find the original concentration:

0.00375 mol / 0.015 L = 0.25 mol/L

The concentration of H₂SO₄ being neutralized is 0.25 M.
6 0
3 years ago
When may a scientific theory be revised
harina [27]

Answer:

A theory doesn’t change into a scientific law because of new or better evidence.

Explanation:

A theory will always remain a theory, and i law will remain a law. The reason being that theories and laws may differ on account of newfound countervailing evidence. Remember, theories and laws are very different from hypotheses.

8 0
3 years ago
If an atom has an equal number of electrons and protons, it would be considered ________
quester [9]
It would be considered NEUTRAL
4 0
4 years ago
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