Answer:
Q = 60192 j
Explanation:
Given data:
Volume of water = 0.45 L
Initial temperature = 23°C
Final temperature = 55°C
Amount of heat absorbed = ?
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 55°C - 23°C
ΔT = 32°C
one L = 1000 g
0.45 × 1000 = 450 g
Specific heat capacity of water is 4.18 j/g°C
Q = m.c. ΔT
Q = 450 g. 4.18 j/g°C. 32°C
Q = 60192 j
Answer:
6 C(s) + 3 O₂(g) + 2 Fe₂O₃(s) → 4 Fe(s) + 6 CO₂(g)
Explanation:
Iron can be formed in two steps.
Step 1: 2 C(s) + O₂(g) → 2 CO(g)
Step 2: Fe₂O₃(s) + 3 CO(g) → 2 Fe(s) + 3 CO₂(g)
In order to get the net chemical equation, we will multiply the first step by 3, the second step by 2, and then add them.
6 C(s) + 3 O₂(g) → 6 CO(g)
+
2 Fe₂O₃(s) + 6 CO(g) → 4 Fe(s) + 6 CO₂(g)
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6 C(s) + 3 O₂(g) + 2 Fe₂O₃(s) + 6 CO(g) → 6 CO(g) + 4 Fe(s) + 6 CO₂(g)
6 C(s) + 3 O₂(g) + 2 Fe₂O₃(s) → 4 Fe(s) + 6 CO₂(g)
