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Amiraneli [1.4K]
3 years ago
13

How many atoms are there in 90.2 g of selenium?

Chemistry
1 answer:
tia_tia [17]3 years ago
3 0

Answer:First calculate the moles of selenium by multiplying the mass x molar mass 90.2 × 78.96 = 7122.2 moles. Number of moles multiplied by ...

Explanation:

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A student pours 10.0 g of salt into a container of water and observes the amount of time it takes for the salt to dissolve. She
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It will go faster each time because she is stirring therefore the water can get to the salt faster than it just sitting at the top

Explanation:

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List the types of electricity
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There are 2 types of electricity, static electricity and current electricity
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What is Li+1 atomic mass
zvonat [6]

Answer:

7.941

Explanation:

You can look at a picture of the periodic table.To calculate the atomic mass of a single atom of an element, add up the mass of protons and neutrons. Example: Find the atomic mass of an isotope of carbon that has 7 neutrons. You can see from the periodic table that carbon has an atomic number of 6, which is its number of protons.

Hope I helped

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3 years ago
Which actions represent endothermic reactions? Check all that apply. an instant ice pack becoming cold, splitting a gas molecule
DerKrebs [107]
Answer is: an instant ice pack becoming cold, splitting a gas molecule and baking bread.

<span>Endothermic reaction is chemical reaction that absorbs more energy than it releases.
</span>In ice pack, <span>reaction absorbs heat from the surroundings (endothermic reaction), lowering the surrounding temperature.
For splitting molecule and baking bread we must add energy to break bonds between atoms.</span>
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3 years ago
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What is the mass (grams) of salt in 10.0 m' of ocean water? ball park-4x10's (1.000 molsalt -58.44 g salt, 1.0 L ocean water -0.
koban [17]

Answer:

3.5 × 10⁵ g of salt

Explanation:

<em>What is the mass (grams) of salt in 10.0 m³ of ocean water?</em>

We have this data:

  • 1.000 mol salt is equal to 58.44 g salt
  • 1.0 L of ocean water contains 0.60 mol of salt

We will need the following relations:

  • 1 L = 1dm³
  • 1 m³ = 10³ dm³

We can use proportions:

10.0m^{3} .\frac{10^{3}dm^{3}  }{1m^{3} } .\frac{1L}{1dm^{3} } .\frac{0.60molSalt}{1.0L} .\frac{58.44gSalt}{1molSalt} =3.5 \times 10^{5} gSalt

8 0
3 years ago
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