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Norma-Jean [14]
3 years ago
13

Solve the equation. 12x – 15 = 3(2x +3)

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
8 0

Answer:

x = 4

Step-by-step explanation:

Solve for x:

12 x - 15 = 3 (2 x + 3)

Hint: | Write the linear polynomial on the left hand side in standard form.

Expand out terms of the right hand side:

12 x - 15 = 6 x + 9

Hint: | Move terms with x to the left hand side.

Subtract 6 x from both sides:

(12 x - 6 x) - 15 = (6 x - 6 x) + 9

Hint: | Combine like terms in 12 x - 6 x.

12 x - 6 x = 6 x:

6 x - 15 = (6 x - 6 x) + 9

Hint: | Look for the difference of two identical terms.

6 x - 6 x = 0:

6 x - 15 = 9

Hint: | Isolate terms with x to the left hand side.

Add 15 to both sides:

6 x + (15 - 15) = 15 + 9

Hint: | Look for the difference of two identical terms.

15 - 15 = 0:

6 x = 9 + 15

Hint: | Evaluate 9 + 15.

9 + 15 = 24:

6 x = 24

Hint: | Divide both sides by a constant to simplify the equation.

Divide both sides of 6 x = 24 by 6:

(6 x)/6 = 24/6

Hint: | Any nonzero number divided by itself is one.

6/6 = 1:

x = 24/6

Hint: | Reduce 24/6 to lowest terms. Start by finding the GCD of 24 and 6.

The gcd of 24 and 6 is 6, so 24/6 = (6×4)/(6×1) = 6/6×4 = 4:

Answer:  x = 4

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The sum of the ages of Arturo, Benny, and Carlos is 41 years. Twice Arturo's age exceeds the sum of Benny and Carlos's ages by o
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Answer: Arturo is 14 years

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Step-by-step explanation:

Let x represent the age of Arturo.

Let y represent the age of Benny.

Let z represent the age of Carlos.

The sum of the ages of Arturo, Benny, and Carlos is 41 years. It means that

x + y + z = 41- - - - - - - - - - - - -1

Twice Arturo's age exceeds the sum of Benny and Carlos's ages by one year. It means that

2x = y + z + 1- - - - - - - - - 2

Five years ago, Benny was 2 years more than twice as old as Carlos. It means that

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Substituting y = 2z - 3 into equation 2, it becomes

2x = 2z - 3 + z + 1

2x = 2z + z - 3 + 1

2x = 3z - 2

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Substituting y = 2z - 3 and

x = 3z/2 - 1 into equation 1, it becomes

3z/2 - 1 + 2z - 3 + z = 41

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z = 10

x = 3z/2 - 1 = (3 × 10)/2 - 1

x = 14

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