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2 years ago

Solve the equation. 12x – 15 = 3(2x +3)

Mathematics

1 answer:

MA_775_DIABLO [31]2 years ago

8 0

Answer:

x = 4

Step-by-step explanation:

Solve for x:

12 x - 15 = 3 (2 x + 3)

Hint: | Write the linear polynomial on the left hand side in standard form.

Expand out terms of the right hand side:

12 x - 15 = 6 x + 9

Hint: | Move terms with x to the left hand side.

Subtract 6 x from both sides:

(12 x - 6 x) - 15 = (6 x - 6 x) + 9

Hint: | Combine like terms in 12 x - 6 x.

12 x - 6 x = 6 x:

6 x - 15 = (6 x - 6 x) + 9

Hint: | Look for the difference of two identical terms.

6 x - 6 x = 0:

6 x - 15 = 9

Hint: | Isolate terms with x to the left hand side.

Add 15 to both sides:

6 x + (15 - 15) = 15 + 9

Hint: | Look for the difference of two identical terms.

15 - 15 = 0:

6 x = 9 + 15

Hint: | Evaluate 9 + 15.

9 + 15 = 24:

6 x = 24

Hint: | Divide both sides by a constant to simplify the equation.

Divide both sides of 6 x = 24 by 6:

(6 x)/6 = 24/6

Hint: | Any nonzero number divided by itself is one.

6/6 = 1:

x = 24/6

Hint: | Reduce 24/6 to lowest terms. Start by finding the GCD of 24 and 6.

The gcd of 24 and 6 is 6, so 24/6 = (6×4)/(6×1) = 6/6×4 = 4:

Answer: x = 4

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Komok [63]

The quotient of the number given number 7 Superscript negative 1 Baseline Over 7 Superscript negative 2 Baseline is 7.

<h3>What is the quotient?</h3>

Quotient is the resultant number which is obtain by dividing a number with another. Let a number a is divided by number b. Then the quotient of these two number will be,

$q=\dfrac{a}{b}$

Here, (<em>a, b</em>) are the real numbers.

The number StartFraction 7 Superscript negative 1 Baseline Over 7 Superscript negative 2 Baseline EndFraction, given can be written as,

$\dfrac{7^{-1}}{7^{-2}}$

Let the quotient of this division is n. Therefore,

$n=\dfrac{7^{-1}}{7^{-2}}$

A number in numerator of a fraction with negative exponent can be written in the denominator with the same but positive exponent and vise versa. Therefore,

$n=\dfrac{7^{2}}{7^{1}}\\n=7$