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3 years ago

9

Why can i keep giving brainlyest? they should make it like every day you can give 1

1 answer:

defon3 years ago

6 0

That’s true!!!! They totally should do that!

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How do I solve log(2)t^3-1=-3?

Ne4ueva [31]

Assuming you mean
$log_2(t^3-1)=-3$
remember
$log_a(b)=c$ translates to $a^c=b$
translate

$log_2(t^3-1)=-3$ translates to $2^{-3}=t^3-1$
$\frac{1}{2^3} =t^3-1$
$\frac{1}{8} =t^3-1$
add 1 to both sides
$\frac{9}{8} =t^3$
cube root both sides
$\frac{ \sqrt[3]{9} }{2}=t$

3 0

3 years ago

Andrea enjoys running. She keeps a daily journal to record how far she runs. She wears a pedometer to calculate the exact distan

Neko [114]

Answer:

14.225 kilometers.

Step-by-step explanation:

Monday 3.6

Tuesday 4.705

Wednesday 5.92

By using the addition operation, the total distance, in kilometers, that Andrea ran over the three days will be :

3.6 +4.705 +5.92=14.225

Hence, the total distance that Andrea ran over the three days = 14.225 kilometers.

5 0

3 years ago

The James family hosted an independent day party they expected 70 gusts but 7 times fewer showed up how many phone attend the pa

Finger [1]

Answer:10 people

Step-by-step explanation:

7 times less showed up so, 70 divided by 7 is 10. 10 guests attended.

5 0

3 years ago

Identify the domain and range of the relation:<br> (-5,-3), (-2,1), (1,4), (2,5)

jonny [76]

Domain is the x-coordinate and range is the y - coordinate

$\therefore \: domain = \{ - 5, \: - 2, \: 1, \: 2 \} \\ \\ \&\: range = \{ - 3, \: 1, \: 4, \: 5\}$

3 0

3 years ago

PLEASE HELP NEED THIS ANSWERED CORRECTLY

Helen [10]

f(3) = 1.9

Solution:

Given function:

$$f(x)=\frac{14}{7+2 e^{-0.6 x}}$

To find f(3):

Substitute x = 3 in the given function.

$$f(3)=\frac{14}{7+2 e^{-0.6 (3)}}$

$$f(3)=\frac{14}{7+2 e^{-1.8}}$

Let us first simplify $2e^{-1.8}$ .

Apply exponent rule: $a^{-b}=\frac{1}{a^{b}}$

$2e^{-1.8}=2\frac{1}{e^{1.8}}$

The value of $e^{1.8}=6.04964$ . (using calculator)

$$\frac{2}{e^{1.8}}=\frac{2}{6.04964}=0.33059$

$2e^{-1.8}=0.33059$

Substitute this value in f(3).

$$f(3)=\frac{14}{7+0.33059}$

$$f(3)=\frac{14}{7.33059}$

$$f(3)=1.90980$

f(3) = 1.9

Hence the value of f(3) is 1.9.

3 0

3 years ago