Answer:
k = 200 N/m
Explanation:
given,
mass of the object = 251 g
= 251 x 10⁻³ Kg = 0.251 Kg
distance of tendon stretch = x = 1.23 cm
= 1.23 x 10⁻² = 0.0123 m
using the formula
F = k x
where
k is the force constant of the tendon
F = m g
F = 0.251 x 9.8 = 2.4598 N
2.4598 = k x 0.0123
k = 199.98 N/m
k = 200 N/m
hence, force constant of the tendon is approximately equal to 200 N/m
The distance covered by the body is 114.3 m
Explanation:
The work done by a force exerted on an object is given by
where
F is the magnitude of the force
d is the displacement of the object
is the angle between the direction of the force and of the displacement
For the object in this problem, we have
F = 350 N is the force applied
is the work done
if we assume that the force is applied parallel to the motion of the object
Solving for d, we find the distance covered by the object:
Learn more about work:
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Answer: So finally, the dimensional formula of the radius of gyration will be written as: [M0LT0]. The power of zero on the dimension of the mass and time shows that the mass and the time dimensions are zero for the radius of gyration. Hope this helps (:
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