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Vadim26 [7]
3 years ago
5

How long will it take a car to go from a complete stop to 44km/h if they are accelerating at 5km/h

Physics
1 answer:
Ber [7]3 years ago
4 0

Explanation:As always, if the relation does not come to mind immediately, take a glance at the basic kinematic equations of constant acceleration

what do we know? Vi start speed; Vf terminal speed; acceleration a; and we want to know time t. Three of the relations have a term in d distance - which we don’’t know. That leaves this one: Vt = Vi + a*t. Here we go then:

44 = 0 + 5 * t so t = 44 / 5 = 8.8 hours

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An electric travel blanket uses a car's 12V supply. The current is 3A.
snow_lady [41]

For electrical devices . . .

           Power dissipated = (voltage) x (current) =

                                             (12 V)  x  (3.0 A) = 36 watts .

1 watt means 1 joule per second

           (36 joule/sec) x (60 sec/min) x (10 min)  =  21,600 joules

5 0
2 years ago
In a mass spectrometer a particle of mass m and charge q is accelerated through a potential difference V and allowed to enter a
Ghella [55]

Answer:

m = B²qR² / 2 V

Explanation:

If v be the velocity after acceleration under potential difference of V

kinetic energy  = loss of electric potential energy

1/2 m v² = Vq ,

v² = 2 Vq / m ----------------------- ( 1 )

In magnetic field , charged particle comes in circular motion in which magnetic force provides centripetal force

magnetic force = centripetal force

Bqv = mv² / R

v = BqR / m

v² = B²q²R² / m²  ------------------------- (2)

from (1) and (2)

B²q²R² / m²  = 2 Vq / m

m = B²q²R² / 2 Vq

m = B²qR² / 2 V

7 0
3 years ago
9. A 5.0 kg block on an inclined plane is acted upon by a horizontal force of 100 N shown in the figure below. The coefficient o
Helga [31]

Answer:

A: The acceleration is 7.7 m/s up the inclined plane.

B: It will take the block 0.36 seconds to move 0.5 meters up along the inclined plane

Explanation:

Let us work with variables and set

m=5kg\\\\F_H=100N\\\\\mu=0.3\\\\\theta=37^o.

As shown in the attached free body diagram, we choose our coordinates such that the x-axis is parallel to the inclined plane and the y-axis is perpendicular. We do this because it greatly simplifies our calculations.

Part A:

From the free body diagram we see that the total force along the x-axis is:

F_{tot}=mg*sin(\theta)+F_s-F_Hcos(\theta).

Now the force of friction is F_s=\mu*N, where N is the normal force and from the diagram it is F_y=mg*cos(\theta).

Thus F_s=\mu*N=\mu*mg*cos(\theta).

Therefore,

F_{tot}=mg*sin(\theta)+\mu*mg*cos(\theta)-F_Hcos(\theta)\\\\=mg(sin(\theta)+\mu*cos(\theta))-F_Hcos(\theta).

Substituting the value for F_H,m,\mu, and \:\theta we get:

F_{tot}= -38.63N.

Now acceleration is simply

a=\frac{F_H}{m} =\frac{-38.63N}{5kg} =-7.7m/s.

The negative sign indicates that the acceleration is directed up the incline.

Part B:

d=\frac{1}{2} at^2

Which can be rearranged to solve for t:

t=\sqrt{\frac{2d}{a} }

Substitute the value of d=0.50m and a=7.7m/s and we get:

t=0.36s.

which is our answer.

Notice that in using the formula to calculate time we used the positive value of a, because for this formula absolute value is needed.

5 0
3 years ago
1 point
klio [65]

Answer:

0

10

20

30

40

50

60

70

80

90

100 g

0

100

200

300

400

500

8

9

108

Explanation:

ikkk

8 0
3 years ago
What does every magnet possess?
IRINA_888 [86]

Answer:

a North and South Pole :)

Explanation:

5 0
3 years ago
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