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3 years ago

Anyone know how to do this ?

Mathematics

2 answers:

Molodets [167]3 years ago

7 0

If x is given 3
Then we have to put in the equation
Y= -x^2
We put 3 in the place of x
Y= -3^2
Now, we multiply -3 times -3 we get 9
Y= 9

So, if the x=3 then the y=9

Explanation
We can also write this in graphic form (3,9)

slava [35]3 years ago

5 0

Answer:

Ahh! I know right?

Step-by-step explanation:

So what it's talking about is a "Function box", a method used to by teachers to introduce functions. My teacher introduced it as a "FUN-ction box"

So X in this case is being represented as the input, and y as the output. So, we have to find y when x is 3.

Simple!

Just input 3 for x and you will solve it!

$y=-(3)^{2} \\y=-9$

See? Simple.

Hope this helps!

P.S. How's your Apocalypse going?

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If this particular arithmetic sequence, a7=34 and a15=74. What is the value of a21

Ilya [14]

This is an arithmetic sequence, meaning, to get the next term, you simply add some value to the current one, namely the "common difference" "d".

now, we know the 17th term is 34, let's go to the 15term then

34 + d
34 + d + d
34 + d + d + d
34 + d + d + d + d
34 + d + d + d + d + d
34 + d + d + d + d + d + d
34 + d + d + d + d + d + d + d
34 + d + d + d + d + d + d + d + d

now, notice, we got to the 15th term, which is 34 + d + d + d + d + d + d + d + d, or namely 34 + 8d, it just so happen we know is 74, therefore,

$\bf 34+8d=74\implies 8d=40\implies d=\cfrac{40}{8}\implies \boxed{d=5}$

ok, now that we know what the common difference is, let's find the first term in the sequence using the 7th term of 34,

$\bf n^{th}\textit{ term of an arithmetic sequence}\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
n=7\\
d=5\\
a_7=34
\end{cases}
\\\\\\
a_7=a_1+(7-1)5\implies 34=a_1+(7-1)5
\\\\\\
34=a_1+30\implies \boxed{4=a_1}$

and now let's use those 2 found folks, to get the 21st term,

$\bf n^{th}\textit{ term of an arithmetic sequence}\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
a_1=4\\
d=5\\
n=21
\end{cases}
\\\\\\
a_{21}=4+(21-1)5\implies a_{21}=4+100\implies a_{21}=104$

3 0

3 years ago

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Semenov [28]

Answer:

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Step-by-step explanation:

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3 years ago

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iragen [17]

Answer:

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Step-by-step explanation:

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3 years ago

A company pays 75 percent of each employee's medical care premium. If the employee portion is $50 per month and there are 100 em

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3 years ago

Read 2 more answers

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Rus_ich [418]

Answer:

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Step-by-step explanation:

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3 years ago