A > Is the correct answer :)
The mass of Jupitar is obtained from the calculations as 5.8 * 10^-14 Kg.
<h3>What is the mass of Jupitar?</h3>
There are nine planets in the solar system and the sun lies at the enter of our solar system. This is the heliocentric model of the solar system.
Given that;
T^2 = GMr^3/4π
T = period
G = gravitational constant
r = radius
M = mass of Jupitar
Now;
1 day = 86400 seconds
1.77 days = 1.77 days * 86400 seconds/1 day
= 152928 seconds
Making M the subject of the formula;
M =4πT^2/Gr^3
M = 4 * 3.142 * (152928)^2/6.67 × 10^-11 * (422 × 10^9)^3
M = 2.9 * 10^11/5.0 * 10^24
M = 5.8 * 10^-14 Kg
Learn more about mass of a planet:brainly.com/question/13851553
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Point A has the largest magnitude of acceleration as compared to other points on the position verses time graph.
On the graph, A is the point where magnitude of the acceleration of the particle is greatest as compared to other positions on the graph because the height of point A is the largest as compared to other points of the graph.
The graph shows at which point acceleration of an object is higher and lower so we can conclude that point A has the largest magnitude of acceleration as compared to other points on the position verses time graph.
Learn more about acceleration here: brainly.com/question/933224
Learn more: brainly.com/question/25887663
Answer:
3 years
Explanation:
Find the circumference of each orbit in AU.
2xπx1=6.283185307
2xπx3=18.84955592
Divide them.
18.84955592/6.283185307=3
3 years
