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Aloiza [94]
2 years ago
11

You roll a​ six-sided die. Find the probability of each of the following scenarios. ​(a) Rolling a 5 or a number greater than 3.

​(b) Rolling a number less than 5 or an even number. ​(c) Rolling a 2 or an odd number
Mathematics
1 answer:
sertanlavr [38]2 years ago
7 0

Answer:

Step-by-step explanation:

a.

let A= number 5

B=number >3

P(A)=1/6  {5}

P(B)=3/6  {4,5,6}

p(A∩B)=1/6   {5}

P(AUB)=P(A)+P(B)-P(A∩B)=1/6+3/6-1/6=3/6=1/2

b.

let  event C=number<5

D=even number

C=[1,2,3,4}

D={2,4,6}

C∩D={2,4}

P(C)=4/6

P(D)=3/6

P(C∩D)=2/6

P(C∪D)=P(C)+P(D)-P(C∩D)=4/6+3/6-2/6=5/6

c.

let event E=number 2

F= an odd number.

E={2}

F={1,3,5}

E∩F={}

P(E)=1/6

P(F)=3/6

P(E∩F)=0

P(E∪F)=P(E)+P(F)-P(E∩F)=1/6+3/6-0=4/6=2/3

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2 years ago
I have five apples and ten oranges. If a fruit basket must contain at least one piece of fruit, how many kinds of fruit baskets
liq [111]

Answer:

65

Step-by-step explanation:

First, let's consider the case where you have 1 apple in the basket. The possible number of baskets you can have with 1 apple is 11: the case where you have no oranges besides the apples, the case where you have 1 orange, the case where you have 2 orange, etc.

This line of reasoning can be followed by each possible amount of apples you can have: 0, 1, 2, 3, 4 and 5.

Keep in mind that in the case where you have no apples, you must exclude the case where you also have no oranges, because the problem tells you that the basket must have at least 1 fruit.

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2 years ago
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Answer:

7.8655

Step-by-step explanation:

Given the functionl

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Where,

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We obtain U"(x), then we have

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On the grid draw graphs of y=x+2 and x+y=3
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Hopes this Helps!!!

Sincerly Barry

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