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Ipatiy [6.2K]
1 year ago
12

Please help me which one

Chemistry
1 answer:
mel-nik [20]1 year ago
3 0
Non of the above because protons and neutrons don’t mix with each one there
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What is the mole fraction of NaCl in a mixture containing 7.21 moles NaCl, 9.37 moles KCL, and 3.42
GrogVix [38]

Answer : The mole fraction of NaCl in a mixture is, 0.360

Explanation : Given,

Moles of NaCl = 7.21 mole

Moles of KCl = 9.37 mole

Moles of LiCl = 3.42 mole

Now we have to calculate the mole fraction of NaCl.

\text{Mole fraction of }NaCl=\frac{\text{Moles of }NaCl}{\text{Moles of }NaCl+\text{Moles of }KCl+\text{Moles of }LiCl}

Now put all the given values in this formula, we get:

\text{Mole fraction of }NaCl=\frac{7.21}{7.21+9.37+3.42}=0.360

Therefore, the mole fraction of NaCl in a mixture is, 0.360

3 0
3 years ago
The octet rule pertains to:
Vinil7 [7]
I think the answer to c
4 0
3 years ago
Heat and pressure deep in the earth change shale to slate. Why does this happen?
dedylja [7]

Answer:

Because of the ground above and the molten iron core.

Explanation:

As you go deeper into the earth you have more and more of the earth above you that applies pressure on you. The heat near the very top of the plate is relatively low and it decreases by a little as you go down. But once you start to go down into the earth by hundreds of meters then the temperature starts to rise and it rises pretty quickly due to the heat being transferred from the molten iron outer core of the earth.

5 0
3 years ago
Can someone help me with this
lord [1]

Answer: A

Explanation:

8 0
2 years ago
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Which correctly describes the reaction between potassium and excess water?
nika2105 [10]
Balanced chemical reaction: 2K(s) + 2H₂O(l) → 2KOH(aq) + H₂(g).

KOH is inorganic compound p<span>otassium hydroxide, a strong base.
H</span>₂ is hydrogen gas.
In balanced chemical reaction number of atoms on both side of chemical reaction must be same. There are two potassium atoms, four hydrogen atoms and two oxygen atoms on both side of reaction.
7 0
3 years ago
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