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anygoal [31]
4 years ago
11

A student is doing an experiment to determine the effects of temperature on an object. He writes down that the initial temperatu

re of the object was –3.5 ºK. Identify two errors in the student’s recorded temperature.
Chemistry
1 answer:
bogdanovich [222]4 years ago
6 0

Answer:

1) The Kelvin temperature cannot be negative

2) The Kelvin degree is written as K, not ºK

Explanation:

The temperature of an object can be written using different temperature scales.

The two most important scales are:

- Celsius scale: the Celsius degree is indicated with ºC. It is based on the freezing point of water (placed at 0ºC) and the boiling point of water (100ºC).

- Kelvin scale: the Kelvin is indicated with K. it is based on the concept of "absolute zero" temperature, which is the temperature at which matter stops moving, and it is placed at zero Kelvin (0 K), so this scale cannot have negative temperatures, since 0 K is the lowest possible temperature.

The expression to convert from Celsius degrees to Kelvin is:

T(K)=T(^{\circ}C)+273.15

Therefore  in this problem, since the student reported a temperature of -3.5 ºK, the errors done are:

1) The Kelvin temperature cannot be negative

2) The Kelvin degree is written as K, not ºK

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Ksju [112]

Answer:

nearer to the north pole

Explanation:

because there is more water, which is basically gone everywhere else on Mars except for the south pole which has less water than the north pole

7 0
3 years ago
For the following reaction, the equilibrium constant Kc is 0.80 at a certain temperature. If the concentration of NO(g) and NOBr
velikii [3]

Answer:

[Br₂] =  1.25M

Explanation:

        2NO (g)  +  Br₂ (g)   ⇄   2NOBr (g)

Eq    0.80M            ?                0.80M

That's the situation told, in the statement.

Let's make the expression for Kc

Kc = [NOBr]² / [Br₂] . [NO]²

Kc = 0.80² / [Br₂] . [0.80]²

0.80 = 1 / [Br₂]

[Br₂] = 1 / 0.80 → 1.25

4 0
3 years ago
The ______ force is equal to the weight of the fluid displaced by an object. gravitational friction buoyant
Tju [1.3M]
Buoyant



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8 0
3 years ago
Read 2 more answers
DIMENSIONAL ANALYSIS PLSSSS<br>convert 19 inches to feet(show work)
Anna [14]

19 in = 1.6 ft

You know that

12 in = 1 ft

If you divide both sides by 12 in, you get the <em>conversion factor</em>: 1 = 1 ft/12 in.

If you divide both sides by 1 ft, you get the <em>conversion factor</em>: 12 in/1 ft = 1.

Both are conversion factors because they <em>both equal one</em> and <em>multiplying a measurement by one does not change its value</em>.

You choose the conversion that gives you the correct dimensions for your answer. It must have the correct dimensions <em>on top</em> (in the numerator),

Thus, to convert 19 in to ft, you use the conversion factor with “ft” on the top.

∴ Length = 19 in × (1 ft/12 in) = 1.6 ft

6 0
3 years ago
Calculate the molecular weight of freon-12, if 122.70 liters of its vapor at 200.00
ICE Princess25 [194]

PV = nRT

Where:


P = pressure in atm = 700/760 = 0.9211atm


V = volume = 8.29L


R = gas constant, 0.08206 atm-L/mol-K


T = temperature in Kelvin = 200 + 273 = 473


n = numbers of moles  = Mass/molar mass


mass of the compound = 30.5


we can rewrite the equation above as


PV = (Mass)/(Molar mass) * RT







7 0
3 years ago
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