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saul85 [17]
2 years ago
12

substance x reacts with sodium carbonate to form a gas . The gas turns lime water cloudy. What is substance K and which process

takes place in the reaction?
Chemistry
2 answers:
alexandr402 [8]2 years ago
6 0

When sodium carbonate reacts with hydrochloric acid, Carbon dioxide gas is released. Pass the gas through calcium hydroxide,the solution turns milky indicating that the gas is Carbon dioxide .

The substance K is hydrochloric acid and this is called as neutralisation.

hope this helps u

◌⑅⃝●♡⋆♡MICKZMINNZ♡⋆♡●⑅◌

Alexxx [7]2 years ago
3 0

Answer:

Substance K is hydrochloric acid and the process is neutralisation

Step-by-step explanation:

When you react hydrochloric acid and sodium carbonate, you produce sodium chloride, carbon dioxide and water

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If you react 2.00 g of hydrogen completely using 15.87 g of oxygen to produce water, how much water (in grams) will you have?
leonid [27]

Answer:

The amount (mass) of water we will have is 17.869 grams

Explanation:

The molar mass of hydrogen gas H₂ = 2.016 grams/mole

The molar mass of oxygen gas = 31.999 g/mol

Therefore, 2.00 g of hydrogen will give;

2.00/2.016 = 0.9921 moles of H₂ gas and

15.87 g of O₂ will give;

15.87/31.999 = 0.49595 moles

The reaction is as follows;

2H₂ (g) + O₂ (g) → 2H₂O (l)

Two moles of H₂ react with one mole of O₂ to produce two moles of H₂O

Therefore 0.9921 moles of H₂ will react with 0.9921/2 or 0.49595 moles of O₂ to produce 0.9921 moles of H₂O

From the above we note that all the H₂ and O₂ are completely consumed to form 0.9921 moles of H₂O

Molar mass of H₂O = 18.01528 g/mol

Number of moles = Mass/(Molar mass)

∴ Mass of H₂O = (Molar mass) × (Number of moles)

= 18.01528 g/mol × 0.9921 moles = 17.869 grams

Therefore the amount (mass) of water we will have = 17.869 grams.

8 0
3 years ago
The freezing-point depression of a 0.100 m MgSO4 solution is 0.225°C. Determine the experimental van't Hoff factor of MgSO4 at t
Andrews [41]

<u>Answer:</u> The experimental van't Hoff factor is 1.21

<u>Explanation:</u>

The expression for the depression in freezing point is given as:

\Delta T_f=iK_f\times m

where,

i = van't Hoff factor = ?

\Delta T_f = depression in freezing point  = 0.225°C

K_f = Cryoscopic constant  = 1.86°C/m

m = molality of the solution = 0.100 m

Putting values in above equation, we get:

0.225^oC=i\times 1.86^oC/m\times 0.100m\\\\i=\frac{0.225}{1.86\times 0.100}=1.21

Hence, the experimental van't Hoff factor is 1.21

7 0
3 years ago
When water freezes into ice, sme of the properties have changed <br> What stays the same
larisa86 [58]
When water freezes into ice, some of the properties have change. What stays the same.




Answer: 1: Ice Melting is a physical change. When liquid water (H2O) freezes into a solid state (ice), it appears changed; However, this change is only physical as the the composition of the constituent molecules is the same: 11.19% hydrogen and 88.81% oxygen by mass.


Have a goood day!
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3 years ago
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WARRIOR [948]

Answer:

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Explanation:

its in the book

8 0
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5 0
3 years ago
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