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ivolga24 [154]
2 years ago
12

Find the value of x x=___

Mathematics
2 answers:
blagie [28]2 years ago
5 0
X=2.8 really hoped i helped!
ss7ja [257]2 years ago
4 0
Answer :

x = 2.8

Hope this helps!
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Can you find the first and third one please!
fenix001 [56]

Answer:

The first ones area is 35 cm squared

The third ones area is 32 cm squared

Step-by-step explanation:

A=1/2H (B1+B2)

35=2.5(8+6)

32=2(7+9)

7 0
3 years ago
Consider the expression 40 + 24. Find the greatest common factor of the two numbers, and rewrite the expression using distributi
serg [7]

Answer:

40 + 24 = 8(5 + 3)

Step-by-step explanation:

Consider the expression 40 + 24. Find the greatest common factor of the two numbers, and rewrite the expression using distributive property

Step 1

We find the GCF

The factors of 24 are: 1, 2, 3, 4, 6, 8, 12, 24

The factors of 40 are: 1, 2, 4, 5, 8, 10, 20, 40

Then the greatest common factor is 8.

Step 2

Rewriting the expression using distributive property.

The factors of 40 and 24 that would give us the sum of 8 is given as 5 and 3

Therefore, using Distributive property

40 + 24 = 8(5 + 3)

5 0
3 years ago
The mean cost of domestic airfares in the United States rose to an all-time high of $385 per ticket (Bureau of Transportation St
saveliy_v [14]

Answer:

a)0.067

b)0.111

c)0.612

d)$687.28

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = $385

Standard Deviation, σ = $110

We are given that the distribution of domestic airfares is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(domestic airfare is $550 or more)

P(x > 550)

P( x > 550) = P( z > \displaystyle\frac{550 - 385}{110}) = P(z > 1.5)

= 1 - P(z \leq 1.5)

Calculation the value from standard normal z table, we have,  

P(x > 550) = 1 - 0.933 = 0.067= 6.7\%

b) P(domestic airfare is $250 or less)

P(x \leq 250) = P(z \leq \displaystyle\frac{250-385}{110}) = P(z \leq -1.22)

Calculating the value from the standard normal table we have,

P( x \leq 250) = 0.111 = 11.1\%

c))P(domestic airfare is between $300 and $500)

P(300 \leq x \leq 500) = P(\displaystyle\frac{300 - 385}{110} \leq z \leq \displaystyle\frac{500-385}{110}) = P(-0.77 \leq z \leq 1.04)\\\\= P(z \leq 1.04) - P(z < -0.77)\\= 0.851 - 0.239 = 0.612 = 61.2\%

P(300 \leq x \leq 500) = 61.2\%

d) P(X=x) = 0.03

We have to find the value of x such that the probability is 0.03.

P(X > x)

P( X > x) = P( z > \displaystyle\frac{x - 385}{110})=0.03

= 1 -P( z \leq \displaystyle\frac{x - 385}{110})=0.03

=P( z \leq \displaystyle\frac{x - 385}{110})=0.997

Calculation the value from standard normal z table, we have,  

\displaystyle\frac{x - 385}{110} = 2.748\\x = 687.28

Hence, the domestic fares must be $687.28 or greater for them to lie in the highest 3%.

7 0
3 years ago
What is the equation of the least squares regression line for the data set?
Rus_ich [418]

hey the answer is y=1.862x−0.138 just took the test!

5 0
3 years ago
20-10 write four equivalent expressions
igor_vitrenko [27]
Here's two. I can't think of any more.


20/10
20-(-10)
5 0
3 years ago
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