Answer:
b)
Explanation:
Normal force, is always directed upward the surface over which is placed the object, and can adopt any value, as required to meet Newton's 2nd Law.
In this case, as the external force on the suitcase pulls upward, in order to counteract the influence of gravity, normal force is less than the weight of the suitcase, as follows:
F + Fn = m*g
⇒ Fn = m*g - F
So, the normal force is equal to the magnitude of the weight of the suitcase (m*g) minus the magnitude of the force of the pull (F) which is the same expressed by the statement b.
Answer:
left side
Explanation:
It's smaller in length but still has a pretty close slope to the right side.
Answer:
v₂ = 3.44 m/s
Explanation:
given,
Dan is gliding on skateboard at = 4 m/s
speed of skateboard = 8 m/s
mass of Dan = 50 Kg
mass of skateboard = 7 Kg
Speed of Dan when his feet hit the ground = ?
Using conservation of momentum
PE(initial) = PE(final)
(M+m)V = m v₁ + M v₂
(50+7)x 4 = 7 x 8 + 50 x v₂
50 x v₂ =172
v₂ = 3.44 m/s
speed of Dan when his feet hit the ground = v₂ = 3.44 m/s
Answer:
10N
Explanation:
Equation: ΣF = ma
Fapp = ma
Fapp = (2kg)(5m/s^2) (im guessing you mean 5.00 m/s^2 not m/s)
Fapp = 10*kg*m/s^2
Fapp = 10N
Answer:
Explanation:
Saturn orbital period
p(s)= 29.46years
Average distance
a(s) = 9.54AU
Venus orbital period
p(v) = 0.62 years
a(v) ?
Using Kepler's third law
a³ ∝p²
a³ = kp²
a³/p² = k
Where
a is the distance if planet from sun
T is the period of the planet
Then,
a(Venus)³/p(venus)² = a(saturn)³/p(saturn)²
a(v)³/p(v)² = a(s)³/p(s)²
a(v) ³/ 0.62² = 9.54³/29.46²
a(v) ³/ 0.62² = 1.0004
a(v)³ = 1.0004× 0.62²
a(v)³ = 0.3846
a(v) = cube root(0.3846)
a(v) = 0.727 AU