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3 years ago

Can y’all help me on number 2

Physics

2 answers:

Temka [501]3 years ago

7 0

Answer:

sure

Explanation:

dedylja [7]3 years ago

7 0

Answer:

250 times 10= 2,500, squared, the answer is <u>25,000</u>

Explanation:

force= mass times acceleration, squared means multiply that number again, since 10 is squared you multiply by ten again

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A 41-turn square coil of area 0.074 m2 and a 123-turn circular coil are both placed perpendicular to the same changing magnetic

vesna_86 [32]

Answer:

<h3>The area of second coil is ≅ 0.025 $m^{2}$ </h3>

Explanation:

Given :

No. of turns in the first coil $N_{1} = 41$

No. of turns in the second coil $N_{2} = 123$

Area of first coil $A_{1} = 0.074 m^{2}$

According to the law of electromagnetic induction,

Induced emf = $-N \frac{d \phi}{dt}$

Where $\phi =$ magnetic flux.

Since given in question emf of both coil is same so we compare above equation.

$-\frac{N_{1} d\phi _{1} }{dt_{1} } = -\frac{N_{2} d\phi _{2} }{dt_{2} }$

$\frac{N_{1} A_{1} dB_{1} }{dt_{1} } = \frac{N_{2} A_{2} dB_{2} }{dt_{2} }$

$A_{2} = \frac{N_{1} A_{1} }{N _{2} }$

$A_{2} = \frac{41 \times 0.074 }{123 }$

$A_{2} = 0.0246 = 0.025 m^{2}$

Therefore, the area of second coil is ≅ 0.025 $m^{2}$

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A large raindrop-the type that lands with a definite splat-has a mass of 0.0014 g and hits your roof at a speed of 8.1 m/s. a. W

DENIUS [597]

Answer

given,

mass of the drop, m = 0.0014 g

speed of the drop, u = 8.1 m/s

a) Change in momentum is equal to impulse

final velocity of the drop, v = 0 m/s

J = m ( v - u )

J = 0.0014 x 10⁻³ x ( 0 - 8.1 )

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b) time, t = 0.37 m s

impact of force = ?

we know

J = F x t

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F = 0.031 N

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A box of mass 12 kg is at rest on a flat floor. The coefficient of static friction between the box and floor is 0.42. What is th

vladimir2022 [97]

As we know that friction force on box is given by

$F_s = \mu_s N$

here we know that

$N = mg$

here we have

m = 12 kg

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now we will have

$F_s = 0.42(12)(9.8)$

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