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iogann1982 [59]
2 years ago
5

PLEASE HELP ASAP 40 PTS + BRAINLIEST TO RIGHT/BEST ANSWER

Mathematics
2 answers:
nadya68 [22]2 years ago
4 0

Answer:

B

Step-by-step explanation:

(-2x³ - 4x²+ 9x² + 18x - 19x - 38 + 40)

÷ (x + 2)

[-2x²(x+2) + 9x(x+2) - 19(x+2) + 40]

÷ (x+2)

-2x² + 9x - 19 + 40/(x+2)

disa [49]2 years ago
3 0

Answer:

b

Step-by-step explanation:

(-2x³ - 4x²+ 9x² + 18x - 19x - 38 + 40)

÷ (x + 2)

[-2x²(x+2) + 9x(x+2) - 19(x+2) + 40]

÷ (x+2)

-2x² + 9x - 19 + 40/(x+2)

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A parking space is 20 feet long. A pickup truck is 6 yards long. How many inches longer is the parking space than the truck
masya89 [10]

1 yard = 3 feet.

Multiply the length of the truck by 3 to get total feet:

6 x 3 = 18 feet.

Subtract the length of the truck from the length of the parking space:

20 - 18 = 2 feet

1 foot = 12 inches.

Multiply 2 feet by 12:

2 x 12 = 24 inches longer.

7 0
3 years ago
Carol walked 1 1/3 miles on Monday. 35/6 miles on Tuesday, and 2 miles on Wednesday. About how far did she walk altogether?
Dmitry_Shevchenko [17]

Answer:

9 1/6 miles

Step-by-step explanation:

Add the mixed number by the improper fraction.

1 + 1/3 + 35/6

Solve the fractions first.

In order to have both of the fractions have the same denominator, find the Least Common Multiple of both of the fractions.

1/3 = 2/6

2/6 + 35/6 = 37/6

Turn the improper fraction into a mixed number by dividing the the numerator by the denominator. When you get your quotient, use the remainder as the new numerator over the denominator.

37/6 = 6 1/6

Now, add the 1.

6 1/6 + 1 = 7 1/6

Now, add the 2 miles that Carol walked on Wednesday.

7 1/6 + 2 = 9 1/6

So, Carol walked about 9 1/6 miles on Monday, Tuesday, and Wednesday all together.

4 0
3 years ago
Read 2 more answers
) For which values of x is f '(x) zero? (Enter your answers as a comma-separated list.) x = (No Response) For which values of x
grigory [225]

Answer:

Check below, please

Step-by-step explanation:

Step-by-step explanation:

1.For which values of x is f '(x) zero? (Enter your answers as a comma-separated list.)

When the derivative of a function is equal to zero, then it occurs when we have either a local minimum or a local maximum point. So for our x-coordinates we can say

 f'(x)=0\: at \:x=2, and\: x=-2

2. For which values of x is f '(x) positive?

Whenever we have  

 f'(x)>0

then function is increasing. Since if we could start tracing tangent lines over that graph, those tangent lines would point up.

 f'(x)>0 \:at [-4,-2) \:and\:(2, \infty)

3. For which values of x is f '(x) negative?  

On the other hand, every time the function is decreasing its derivative would be negative. The opposite case of the previous explanation. So

 f'(x)

4.What do these values mean?

 f(x) \:is \:increasing\:when\:f'(x) >0\\\\f(x)\:is\:decreasing\:when f'(x)

5.(b) For which values of x is f ''(x) zero?

In its inflection points, i.e. when the concavity of the curve changes. Since the function was not provided. There's no way to be precise, but roughly

at x=-4 and x=4

6 0
2 years ago
Pleaseeeeeeees help meee
maria [59]
12, 4 is the answer.
8 0
2 years ago
Read 2 more answers
the temperature of an oven went through 330 degrees to 390 degrees what is the percentage increase in temperature
valentina_108 [34]
All you do is divide. 
330/390= 0.846
round it: 0.85 
Answer is about 85%
5 0
3 years ago
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