Question

Two cities are 210 km apart. A train traveled this distance in 4 2/3 hours and then made the return trip at a speed of 50 2/5 km/h. How many times greater (or less) was the train’s speed on the return trip?

Answer 1

$4 \frac{2}{3}= \frac{14}{3}$

So, $\frac{210km}{ \frac{14}{3}hr }= 45km/h$

$50 \frac{2}{5} = \frac{252}{5}$


So, $\frac{252}{5}/45= 1.12$ times greater on the return trip.