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vlabodo [156]
3 years ago
7

Perform the addition or subtraction and simplify. (20 points)

Mathematics
1 answer:
pentagon [3]3 years ago
7 0
You have to find the LCD or least common denominator.
In this case the LCD would be (x-6)(x+5).

Problem: x/ x-6 - 1/x+5

Step 1: multiply x-6 to the numerator and denominator of 1/x+5

1(x-6)/ (x+5)(x-6)

Step 2: multiply x+5 to the numerator and denominator of x/x-6
x(x+5)/ (x+5)(x-6)

After all that, this is how the problem should look now

x(x+5)/ (x-6)(x+5) - 1(x-6)/ (x-6)(x+5)

If you simplify this you get

x²+5x-x+6/ (x-6)(x+5)

If you subtract both 5x-x (like terms) you get

x²+4x+6/ (x-6)(x+5)
which is the answer

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Parker Middle School's chior needs to raise $480 for an upcoming trip they will take. At their first fundraising project, they r
harkovskaia [24]

The money does the choir still need to raise is $180.

<u>Step-by-step explanation:</u>

The money needed to be raised by the choir for an upcoming trip = $480.

It is given that, the money needed was raised in two fundraising projects.

<u>During the first fundraising project :</u>

The choir raised 25% of the money needed for the trip.

⇒ 25% of 480

⇒ (25/100) × 480

⇒ (1/4) × 480

⇒ 120

Therefore, the first fundraising project raised $120.

<u>During the second fundraising project :</u>

The choir raised 3/8 of the money needed for the trip.

⇒ 3/8 of 480

⇒ (3/8) × 480

⇒ 3 × 60

⇒ 180

Therefore, the second fundraising project raised $180.

<u>To find the money does the choir still need to raise :</u>

You need to find the remaining amount from the 480 after raising money from the two fund raising projects.

For that, find out how much you raised from those fund raising projects and subtract it from the 480.

Money needed = Total money required for the trip - Raised money

⇒ 480 - (120+180)  

⇒ 480 - 300

⇒ 180 dollars.

The money does the choir still need to raise is $180.

6 0
3 years ago
HELP HELP HELP HELP help help
SVETLANKA909090 [29]

Answer:

r  = 6

Step-by-step explanation:

To get the value of r we will use the pythagoras theorem a shown;

PR² = QR² + PQ²

(4+r)² = 8² + r²

Expand

16+8r+r² = 64 + r²

16 + 8r = 64

8r = 64 - 16

8r = 48

r = 48/8

r = 6

Hence the value of r is 6

7 0
3 years ago
Multiply<br><br> 2.5<br> 5.4 =<br><br> ​(Type an integer or a simplified​ fraction.)
zepelin [54]

Answer:

Fractional form of 2.5 is 5/2.

5.4 as a fraction is 27/5.

4 0
3 years ago
Si el lado de un cuadrado mide 10cm cuanto mide él área del círculo que se encuentra adentro de ese cuadrado
Alex17521 [72]

Answer:

El área del círculo que se encuentra en el cuadrado es de 78.5cm²

Step-by-step explanation:

Para resolver este ejercicio tenemos que pensar que un cuadrado tiene sus 4 lados iguales, por lo que todos sus lados medirán 10cm.

Ahora nos fijamos que necesitamos saber para calcular el área de un circulo

a = área

r = radio

π = 3.14

a = π * r²

como podemos ver no sabemos el valor del radio

como el circulo toca con los 4 lados del cuadrado sabemos que su radio sera la distancia del centro del cuadrado a cualquiera de los lados.

Entonces tenemos que dividir un lado por 2

10cm/2 = 5cm

El radio del circulo sera 5cm

Ahora que tenemos todos los datos podemos calcular el valor del área

a = 3.14 * (5cm)²

a = 3.14 * 25cm²

a = 78.5cm²

El área del círculo que se encuentra en el cuadrado es de 78.5cm²

8 0
3 years ago
Given: (↔AB) ║ (↔CD)
nordsb [41]
1) m = y2 - y1/x2 - x1
y = mx + b
m = 7 - 0/3 - 8
y = -7/5x + 11.2
2) y= -7/5x + 12
(the slope or m stays the same because the two equations are parallel)
8 0
3 years ago
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