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ANEK [815]
3 years ago
10

7. At what temperature would 343.01 g of P2O3 gas occupy 67.5 L if the pressure is 115 kPa?

Chemistry
1 answer:
DaniilM [7]3 years ago
6 0

Answer:

26.1°C

Explanation:

T = PV / nR = (115 kPa) x (67.5 L) / ((343.01 g P2O3 / (109.94572 g P2O3/mol)) x (8.3144626 L kPa/K mol)) = 299.3 K = 26.1°C

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