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3 years ago

What is the molarity of a solution made by dissolving .75mol of NaCl in 3.0L of solution?

Chemistry

1 answer:

Murrr4er [49]3 years ago

3 0

Molarity equation is moles/liters so it should be .75/3.0=.25

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Read 2 more answers

A sample of gas is held at 100oc at a volume of 20 L.if the volume is increased to 40 L what is the new temperature of the gas i

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Answer:

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Explanation:

This looks like a case where we can use Charles’ Law:

$\dfrac{V_{1}}{T_{1}} =\dfrac{V_{2}}{T_{2}}$

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$\begin{array}{rcl}\dfrac{V_{1}}{T_{1}}& =&\dfrac{V_{2}}{T_{2}}\\\\ \dfrac{\text{20 L}}{\text{373.15 K}} &=&\dfrac{\text{40 L}}{T_{2}}\\\\{\text{15 000 K}} & = & 20T_{2}\\T_{2} & = &\dfrac{\text{15 000 K}}{20 }\\\\T_{2} & = & \textbf{750 K}\\\end{array}$

Note: The answer can have only two significant figures because that is all you gave for the volumes.

(c) Convert the temperature to Celsius

T₂ = (750 – 273.15) °C = 470 °C

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