Someone please help me with number 11 only please

Which of the following graph is the solution -10<3x-4<8

satela [25.4K]

Answer:

( − 2 , 4 )

Step-by-step explanation:

There were no graphs listed in your question. So...

Convert the inequality to interval notation.

6 0

4 years ago

A hoop, a uniform solid cylinder, a spherical shell, and a uniform solid sphere are released from rest at the top of an incline.

Serjik [45]

Answer:

Step-by-step explanation:

Given

Hoop, Uniform Solid Cylinder, Spherical shell and a uniform Solid sphere released from Rest from same height

Suppose they have same mass and radius

time Period is given by

$t=\sqrt{\frac{2h}{a}}$ ,where h=height of release

a=acceleration

$a=\frac{g\sin \theta }{1+\frac{I}{mr^2}}$

Where I=moment of inertia

a for hoop

$a=\frac{g\sin \theta }{1+\frac{mr^2}{mr^2}}$

$a=\frac{g\sin \theta }{2}$

a for Uniform solid cylinder

$a=\frac{g\sin \theta }{1+\frac{mr^2}{2mr^2}}$

$a=\frac{2g\sin \theta }{3}$

a for spherical shell

$a=\frac{g\sin \theta }{1+\frac{2mr^2}{3mr^2}}$

$a=\frac{3g\sin \theta }{5}$

a for Uniform Solid

$a=\frac{g\sin \theta }{1+\frac{2mr^2}{5mr^2}}$

$a=\frac{5g\sin \theta }{7}$

time taken will be inversely proportional to the square root of acceleration

$t_1=k\sqrt{2}=1.414k$

$t_2=k\sqrt{\frac{3}{2}}=1.224k$

$t_3=k\sqrt{\frac{5}{3}}=1.2909k$

$t_4=k\sqrt{\frac{7}{5}}=1.183k$

thus first one to reach is Solid Sphere

second is Uniform solid cylinder

third is Spherical Shell

Fourth is hoop

3 0

3 years ago

A carnival uses two baskets hanging from springs at different heights. Next to the higher basket is a pile of baseballs. Next to

Lelechka [254]

*I've tried looking up to see if I can find what the part B and c of this question is, but unfortunately, I can't find them. However, I have tried answering this question by answering part a, and also going ahead to answer how to state and explain the secrets of winning the game. I'm pretty sure most of the questions would be answered in the process.

Answer/Step-by-sep explanation:

Using an equation, in slope-intercept form, we can derive an equation that models the relationship of the height of each basket and the number of balls it contains.

The slope-intercept form is given as: $y = mx + b$ , where,

m = slope/rate of change

b = y-intercept/strating value/height of the basket when it's empty.

✍️Baseball Equation:

Using two pairs, (0, 54) and (5, 39) from the given table of values,

Slope/rate of change (m) = $\frac{y_2 - y_1}{x_2 - x_1} = \frac{39 - 54}{5 - 0} = \frac{-15}{5} = -3$ .

y-intercept, b, = the starting value, or the value of y when x = 0. Therefore, b = 54

This means that the baseball basket was at a height of 54 units when it was empty.

m = -3, means the baseball basket kept reducing at an average rate of -3 units in height as each ball was added.

To derive the baseball equation, substitute m = -3, and b = 54 into $y = mx + b$ .

✅Thus, base ball equation would be:

$y = -3x + 54$

✍️Golf Ball Equation:

Using two pairs, (0, 45) and (5, 35) from the given table of values,

Slope/rate of change (m) = $\frac{y_2 - y_1}{x_2 - x_1} = \frac{35 - 45}{5 - 0} = \frac{-10}{5} = -2$ .

y-intercept, b, = the starting value, or the value of y when x = 0. Therefore, b = 45

This means that the golf ball basket was at a height of 45 units when it was empty.

m = -2, means the golf ball basket kept reducing at an average rate of -2 units in height as each ball was added.

To derive the baseball equation, substitute m = -2, and b = 45 into $y = mx + b$ .

✅Thus, golf ball equation would be:

$y = -2x + 45$

Now, to win the game, we have to find out how many number of exact balls (x) we need to add in each basket equally, for both baskets to be at the same height.

To do this, set the equation of the baseball equal to that of the golf ball.

Thus:

$-3x + 54 = -2x + 45$