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4 years ago

This is how manganese appears in the periodic table.

Chemistry

2 answers:

kupik [55]4 years ago

8 0

Answer: The atomic symbol of manganese or Aka D

Explanation: I did the test

Gnesinka [82]4 years ago

6 0

Answer:

d i toke the test

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The concentration of ozone in a sample of air that has a partial pressure of O3 of 0.33 torr and a total pressure of air of 695

Goryan [66]

Answer:

0.047 %

Explanation:

Step 1: Given data

Partial pressure of ozone (pO₃): 0.33 torr

Total pressure of air (P): 695 torr

Step 2: Calculate the %v/v of ozone in the air

Air is a mixture of gases. We can find the %v/v of ozone (a component) in the air (mixture) using the following expression.

%v/v = pO₃/P × 100%

%v/v = 0.33 torr/695 torr × 100%

%v/v = 0.047 %

8 0

3 years ago

What type of bond is this combination likely to form

kari74 [83]

Answer:

A combination is certainly possible, but you should not take formal charges so literally

Normally, when a covalent bond is found, the two atoms both bring in one electron. As you identify correctly, in the case of nitric acid that would not be possible completely. If you draw the different possible resonance structures, the most likely structure has a single bond between the nitrogen and an oxygen where the oxygen has 3 lone pairs and both electrons in the bond are donated by the nitrogen. This makes the nitrogen "positive" and that oxygen "negative", but in fact the electrons move more freely in the molecule and charges are more distributed. You will not be able to find "the negatively charged" oxygen atom.

Explanation:

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4 0

3 years ago

A 10.0-milliliter sample of NaOH(aq) is neutralized by 40.0 milliliters of 0.50 M HCl. What is the molarity of the NaOH(aq)?

Ludmilka [50]

$\frac{10 mL}{1000 mL} = 0.01 L$

$\frac{40mL}{1000mL} =0.04L$

$M _{1} V_{1}=M_{2}V_{2}$

$M_{1}(0.01)=(0.50)(0.04)$

$M_{1}(0.01)=0.02$

$M_{1}= \frac{0.02}{0.01}$

$M_{1}=2$

3 0

4 years ago

1. Calculate the number of moles of carbon dioxide formed when 40.0 moles of oxygen is consumed in the burning of propane. Note

Andrews [41]

Answer:

1. D (24.0 moles CO2)

2. A (.239 moles H2)

Explanation:

1. First Balance the equation

1 C3H8 + 5 O2 ---> 3 CO2 + 4 H2O

Then set up a stoiciometric equation so that the moles of O2 cancel out

40mol O2 x $\frac{3 mole CO2}{5 mole O2}$ = 24.0 moles CO2