Answer:
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Explanation:
<u>Answer:</u> For the given reaction, the value of
is greater than 1
<u>Explanation:</u>
For the given chemical equation:

The expression of
for above equation follows:
![K_c=\frac{[Ca^{2+}]\times [CO_3^{2-}]}{[CaCO_3}]\\\\K_c=[Ca^{2+}]\times [CO_3^{2-}]](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BCa%5E%7B2%2B%7D%5D%5Ctimes%20%5BCO_3%5E%7B2-%7D%5D%7D%7B%5BCaCO_3%7D%5D%5C%5C%5C%5CK_c%3D%5BCa%5E%7B2%2B%7D%5D%5Ctimes%20%5BCO_3%5E%7B2-%7D%5D)
The concentration of pure solids and pure liquids are taken as 1 in equilibrium constant expression
As, the denominator is missing and the numerator is the only part left in the expression. So, the value of
will be greater than 1.
Hence, for the given reaction, the value of
is greater than 1
<span>The set of conditions 1.00 atm pressure and 0.00 oc is defined as pressure.</span>
Nitrogen should be gaining 3 valence electrons.