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Dennis_Churaev [7]
2 years ago
15

10. What is the least number of acute angles a triangle can have?

Mathematics
2 answers:
Leni [432]2 years ago
8 0

Answer:

idk about 12 and 13 but the number of acute angles a triangle can have is 2 and for 11 No, a triangle cannot have an obtuse and a right angle.

Step-by-step explanation:

givi [52]2 years ago
8 0

Answer:

10) 3

11) no

12) kayla's statement is incorrect because the diagonals of a rectangle do not intersect each other at 90 degree like a rhombus.

13) Andy’s statement is incorrect because

Quadrilaterals have 4 sides and 4angles. The exterior angles of any convex polygon add up to 360 degrees ( 4 right angles). If an interior angle is a right angle then the corresponding exterior angle must also be a right angle

Step-by-step explanation:

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The deck that Amos is building is in the shape of a parallelogram, DGRY. The measure of
weqwewe [10]

Complete Question:

The deck that Amos is building is in the shape of a parallelogram, DGRY.  The measure of D is five-halves the measure of Y. Find the measure of  each angle of the deck.

Answer:

\angle G = \angle Y = 51.43 ^{\circ}

\angle D = \angle R = 128.57 ^{\circ}

Step-by-step explanation:

Given

Shape: Parallelogram DGRY

Dimension: \angle D = \frac{5}{2}\angle Y

Required

Find the measure of each angle

D and R are opposite sides & G and Y are also opposite sides.

So, we have:

\angle D = \angle R = \frac{5}{2}\angle Y

and

\angle G = \angle Y

The sum of angles is given as:

\angle D + \angle G + \angle R + \angle Y=360^{\circ}

Substitute values for \angle D, \angle G \ \&  \angle R

\frac{5}{2}\angle Y + \frac{5}{2}\angle Y + \angle Y + \angle Y = 360^{\circ}

Take LCM

\frac{5\angle Y + 5\angle Y + 2\angle Y+ 2\angle Y}{2}= 360^{\circ}

\frac{14\angle Y}{2}= 360^{\circ}

Multiply both sides by \frac{2}{14}

\frac{2}{14} * \frac{14\angle Y}{2}= 360^{\circ} * \frac{2}{14}

\angle Y= 360^{\circ} * \frac{2}{14}

\angle Y= \frac{ 360^{\circ} *2}{14}

\angle Y= \frac{720^{\circ}}{14}

\angle Y= 51.43 ^{\circ}

So:

\angle G = \angle Y = 51.43 ^{\circ}

\angle D = \frac{5}{2}\angle Y

\angle D = \frac{5}{2} * 51.43^{\circ}

\angle D = \frac{5* 51.43^{\circ}}{2}

\angle D = \frac{257.15^{\circ}}{2}

\angle D = 128.57 ^{\circ}

Hence:

\angle D = \angle R = 128.57 ^{\circ}

8 0
2 years ago
Round 5,439 to the nearest thousand​
Murrr4er [49]

Answer:

5,000

Step-by-step explanation:

4 is less than 5 and more so, it will leave the 5 alone

It will also turn everything else into 0's. Making it:

-------------------------------------------------------------------------------

5,000

7 0
3 years ago
2 Which table represents a function? X y X у 2 -3 -3 0 3 0 -2 1 4 -3 -3 2 2 1 2 3 (1) (3) х X у 1 2 AWNIK -4 1 2 1 NO 4. 1 5 4 6
disa [49]
The answer to Which table represent a function is 1
7 0
2 years ago
What divisor is represented by the synthetic division below?  –5 5 x + 5 x – 5
Tju [1.3M]
For this case, the dividend is given by:
 2x ^ 3 + 10x ^ 2 + x + 5

 We note that the following numbers:
 2, 10, 1, 5
 They are the coefficients of the polynomial and they are in the upper part of the division.
 The number -5 is the opposite value of the divisor constant.
 Therefore, the divisor is given by:
 x + 5
 Answer:
 
The divisor is:
 
x + 5
4 0
3 years ago
Read 2 more answers
Do you agree with the statement that " cubic functions must have at least 1 x-intercept but not more than 3, whereas quadratic f
vladimir2022 [97]

Answer:

Yes, I agree

Step-by-step explanation:

For the cubic function

A cubic function is represented as:

f(x)=ax^3+bx^2+cx+d

A cubic function may have 1, 2 or 3 x intercepts. This is shown below

For 3 x intercepts

y = x^3 - x

Equate y to 0

x^3 - x = 0

Expand

x(x^2 - 1) = 0

Express x^2 - 1 as difference of two squares

x(x - 1)(x +1 ) = 0

<em>x = 0 or 1 or -1</em>

For 2 x intercepts

y = x^3 - x

y  =(x-5)^2)(x+7)

Equate y to 0

(x-5)^2(x+7) = 0

Expand

(x-5)(x-5)(x+7) = 0

<em>x= 5 or x = -7</em>

For 1 x intercept

y = x^3

Equate y to 0

x^3 = 0

Take cube roots of both sides

x = 0

It has been shown above that a cubic function may have 1, 2 or 3.

So, I agree to the statement

For the quadratic function

A quadratic function will not have any x intercept when the function can not be factorized;

E.g.

y = x^2 + x + 17

<em>The above function has no x intercept.</em>

A quadratic function will have at least 1 x intercept when the function can be factorized;

E.g.

y = x^2- 6x + 9

Equate y to 0

x^2- 6x + 9 = 0

Expand

x^2 - 3x - 3x + 9 = 0

(x - 3)(x-3) = 0

x = 3

We've shown that a quadratic may have no x intercept, and it may also have x intercept(s)

Hence, I agree to both statement

3 0
2 years ago
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